Answer:
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
Step-by-step explanation:
Let
x ----> the original length pf the piece of metal
y ----> the original width pf the piece of metal
we know that
----> equation A
The volume of the box is equal to
we have
substitute in the formula of volume
----> equation B
substitute equation A in equation B
solve for y
Solve the quadratic equation by graphing
using a graphing tool
The solution is y=21
Find the value of x
therefore
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
Answer:
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Step-by-step explanation:
Answer:
(2.54×12) ×5280
Step-by-step explanation:
Since there are 2.54cm in an inch, multiply 2.54 by 12 to find out how many cm there are in a foot. Then you multiply that by 5280
The answer is 21
By comparing the 4 vertices you can determine the rectangle x-length and y-length. The coordinate for the vertice is:
1,+4i
-2, +4i
-2, -3i
1, -3i
From the coordinate, you can see there are 2 x coordinate(1 and -2) and 2 y coordinate(4i and -3i) that used.
The x-length would be: 1 - (-2)= 3
The y-length would be: 4i- (-3i)= 7i
Then the area of the rectangle would be:
area= x-length * y-length= 3*7=21
