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2 years ago

2+2=?

Mathematics

2 answers:

brilliants [131]2 years ago

8 0

Answer:

It HAS to be ALL OF THE ABOVE, for me.

Step-by-step explanation:

Salsk061 [2.6K]2 years ago

5 0

Answer:

Yes the answer is D ) all of the above :)

Step-by-step explanation:

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You bake 42 chocolate cupcakes and 28 red velvet cupcakes.You package them in boxes that have the same ratio of chocolate to red

blondinia [14]

Answer: 16 red velvet cupcakes.

Step-by-step explanation:

To solve this problem you can apply the following proccedure:

- Let's call the number of red velvet cupcakes in a box that has 24 chocolate cupcakes: $x$

- Based on the information given in the problem, you can set up the following proportion and Solve for $x$ <em>:</em>

$\frac{42}{28}=\frac{24}{x}\\\\1.5x=24\\x=16$

There are 16 red velvet cupcakes in a box that has 24 chocolate cupcakes.

5 0

2 years ago

If the measure of angle ABF=6x+26 and the measure of angle EBF=2x9 and measure of angle ABE= 11x-31 find the measure of angle AB

Hunter-Best [27]

Its not clearly given that whether EBF = 2x + 9 or 2x - 9.

I have written the solution for both.

If EBF = 2x + 9,

then ABF = 6x + 26 and ABE = 11x - 31.

Now, ABE = ABF + EBF

11x - 31 = (6x + 26) + (2x + 9)

= (6x + 2x) + (26 + 9)

= 8x + 35

11x - 8x = 35 + 31

3x = 66

x = 22

Therefore, ABF = 6x + 26 = 6(22) + 26 = 132 + 26 = 158°

If EBF = 2x - 9,

then ABF = 6x + 26 and ABE = 11x - 31.

Now, ABE = ABF + EBF

11x - 31 = (6x + 26) + (2x - 9)

= (6x + 2x) + (26 - 9)

= 8x + 17

11x - 8x = 17 + 31

3x = 48

x = 16

Therefore, ABF = 6x + 26 = 6(16) + 26 = 96 + 26 = 122°

4 0

3 years ago

a large container holds 4 gallons of chocolate milk that has to be poured into bottes. each bottle holds 2 pints.

timama [110]

U can pour it into 16 bottes

5 0

2 years ago

Read 2 more answers

Priya and Tyler are discussing the figures shown below. Priya thinks that B, C, and

Setler [38]

Answer:

No, I do not agree with them. Both are wrong.

Step-by-step explanation:

For a shape or figure to be considered a scaled copy of another, the length of all the segments of scaled copy must be equal to the length of all corresponding segments of the original figure multiplied by the same scale factor.

By examining the scaled copies B, C, and D, we would conclude that only D can be referred to as a scaled copy of D, because all the segments are exactly twice the corresponding segments of A. C and B do not have all its segment scaled in the same proportion.

Therefore, we cannot agree with Priya, nor Tyler. They are both wrong.

7 0

2 years ago

Nurse Jackson examines immunization records for this past winter at the school where she works. Got flu Didn't get flu Total Vac

Harman [31]

Answer:

140

Step-by-step explanation:

ap3x

6 0

2 years ago