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Vlad1618 [11]
3 years ago
6

If you roll two fair sided dice what is the probability that at least one die shows a 3

Mathematics
1 answer:
kobusy [5.1K]3 years ago
8 0
<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

➷ The probability of one die showing a 3 is 1/6

Therefore the probability of the die not showing a 3 is 5/6

As it is 'at least one', you would have to multiply these together:

1/6 x 5/6 = 5/36

As there are 2 dice, you would multiply this value by 2:

5/36 x 2 = 10/72

However, as it is at least one, both could also land on 3

1/6 x 1/6 = 1/36

Add these two fractions together:

10/72 + 1/36 = 1/6

The answer is 1/6

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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So you can do this multiple ways, I'll do this the way that I think makes sense the l most easily.

Cos (0) = 1
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Cos (3pi/2)=0
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Now if you multiply the inside by 4, the graph oscillates more violently (goes up and down more in a shorter period).
But you can always reduce it.
Cos (0)= 1
Cos (4pi/2) = cos (2pi)=1
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etc...
the pattern is that every half pi increase is now a full period as apposed to just a quarter of one. That's in theory.

Now that you know that, the identities of Cosine are another beast, but mathematically.
You have.

Cos (2×2t) = Cos^2 (2t)-Sin^2 (2t)
Sin^2 (t)=-Cos^2 (t)+1..... (all A^2+B^2=C^2)
Cos (2×2t) = Cos^2 (t)-(-Cos^2 (t)+1)
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2Cos^2 (2t) -1= 2 (Cos^2(t)-Sin^2(t))^2 -1
(same thing as above but done twice because it's cos ^2 now)
convert sin^2
2Cos^2 (2t)-1 =2 (Cos^2 (t)+Cos^2 (t)-1)^2 -1
2 (2Cos^2(t)-1)^2 -1
2 (2Cos^2 (t)-1)(2Cos^2 (t)-1)-1
2 (4Cos^4 (t) - 2 (2Cos^2 (t))+1)-1
Distribute

8Cos^4 (t) -8Cos^2 (t) +1

Cos (4t) =8Cos^4-8Cos^2 (t)+-1






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3 years ago
Shelly has a roll of fabric and decides to make some scarves for her friend the roll contains 6 2/3 yards of fabric she needs 5/
ivann1987 [24]

Answer:

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Step-by-step explanation:

Total length of the fabric is 6\dfrac{2}{3}=\dfrac{20}{3}\ \text{yards}

We need to find the number of scarves can she make if she needs 5/6 of a yard for each scarf.

Let she needs x scarves. So, ATQ

x\times \dfrac{5}{6}=\dfrac{20}{3}\\\\x=\dfrac{20}{3}\cdot\dfrac{6}{5}\\\\x=8

Hence, she can make 8 scarves.

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Answer:

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