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Sav [38]
3 years ago
12

what is the volume of a cone if the radius is 6mm and the height is 4mm. Round your answer to the nearest tenth. use 3.14 for pi

. ​
Mathematics
1 answer:
Vladimir79 [104]3 years ago
5 0

Answer:

163.2 cubic millimeters (or) 163.2 mm^3

Step-by-step explanation:

Given: Radius of cone= 6mm

Height of cone= 4mm

π= 3.14(Approximately)

Required: Volume(V)

Volume of cone= 1/3* π* r^2 * h

Volume= 1/3* (3.14) * (6 m)^2 * (4m)

= 1/3* (3.14) * (36) * (4)

= 163.2 mm^3

Therefore, the Volume of the cone is 163.2 mm^3 (to the nearest tenth) :)

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The graph of an equation with a negative discriminant always has which characteristic?
spin [16.1K]

Answer:

The graph does not intercept the x-axis

Step-by-step explanation:

Hi there!

When the discriminant is positive, it means that in the quadratic equation, you <em>can</em> take the square root of this number and end up with two distinct solutions, one negative and one positive. The graph will intercept the x-axis twice.

When the discriminant is zero, it means that you won't be taking the square root of any number in the quadratic equation and you'll end up with two solutions that are equal, or just one distinct solution. The graph will intercept the x-axis once.

When the discriminant is negative, it means that the quadratic has no real solutions, meaning that it does not intercept the x-axis. It is impossible to take the square root of a negative number.

I hope this helps!

7 0
3 years ago
These prisms are similar. Find the surface
Bumek [7]

Answer:

823.7 m^2

Step-by-step explanation:

The ratio of the side lengths is 6/5.

The ratio of the areas is the square of the ratio of the side lengths, 36/25.

572 m^2 * 36/25 = 823.7 m^2

5 0
3 years ago
An ac unit uses 3500 watts or power. If it runs for 10 hours each day and the utility company charges $0.13 per kWh, how much do
Helga [31]

Cost = (3500 W)·(1 kw/1000 W)·(10 hrs/day)·(30 day/month)·($0.13/kw-hr)

Cost = (3500·1·10·30·0.13 / 1000)·(W·kW·hr·da·$ / W·da·month·kw·hr)

Cost = <em> 136.50  $/month</em>

5 0
3 years ago
Pre-Calc: Find all the zeros of the function.
uysha [10]

The zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i and the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

<h3>What are polynomial expressions?</h3>

Polynomial expressions are mathematical statements that are represented by variables, coefficients and operators

<h3>How to determine the zeros of the polynomial?</h3>

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Set the equation to 0

So, we have

(5y - 4)(5y + 4)(25y^2 + 16) = 0

Expand the equation

So, we have

5y - 4 = 0, 5y + 4 = 0 and 25y^2 + 16 = 0

This gives

5y = 4, 5y = -4 and 25y^2 = -16

Solve the factors of the equation

So, we have

y = 4/5, y = -4/5 and y = ±4/5√i

Hence, the zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i

How to write the polynomial as a product of the linear factors?

In (a), we have

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Hence, the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Read more about polynomial at

brainly.com/question/17517586

#SPJ1

5 0
1 year ago
Lisa spends 1/5 of an hour doing her math homework and 1/3 of an hour doing her social studies homework. What fraction of an hou
Sveta_85 [38]
To solve this, all you have to do is add 1/5 and 1/3.
Well, you might be thinking, "But the denominators are not the same! Fractions have to have like denominators in order to be added together!" And you are right. So, all we have to do, is make them both have the same denominator. To do this, we have to multiply both the numerator and denominator by the same number to find an equivalent fraction.
For 1/5, we can multiply both the numerator and denominator by 3, to get 3/15. 
Likewise, we can multiply both the numerator and denominator of 1/3 by 5, to get 5/15.
Now, you can easily add 3/15 and 5/15 because all you have to do is add the numerators, because the denominators are the same!
3/15+5/15=8/15, so she spends 8/15 hour on her math and social studies homework.
Hope I helped!
3 0
3 years ago
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