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Sav [38]
3 years ago
12

what is the volume of a cone if the radius is 6mm and the height is 4mm. Round your answer to the nearest tenth. use 3.14 for pi

. ​
Mathematics
1 answer:
Vladimir79 [104]3 years ago
5 0

Answer:

163.2 cubic millimeters (or) 163.2 mm^3

Step-by-step explanation:

Given: Radius of cone= 6mm

Height of cone= 4mm

π= 3.14(Approximately)

Required: Volume(V)

Volume of cone= 1/3* π* r^2 * h

Volume= 1/3* (3.14) * (6 m)^2 * (4m)

= 1/3* (3.14) * (36) * (4)

= 163.2 mm^3

Therefore, the Volume of the cone is 163.2 mm^3 (to the nearest tenth) :)

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I need help plssssssssss
drek231 [11]

We can say that the area of the figure equals...

5.5 by 9 rectangle - 2 by 2 triangle - 2 by 5 triangle - 9 by 3.5 triangle

5.5 by 9 rectangle = 5.5 x 9 = 49.5 un²

2 by 2 triangle = 1/2 x 2 x 2 = 2 un²

2 by 5 triangle = 1/2 x 2 x 5 = 5 un²

9 by 3.5 triangle = 1/2 x 9 x 3.5 = 15.75 un²

area of figure = 49.5 un² - 2 un² - 5 un² - 15.75 un² = 26.75 un²

answer: 26.75 un²

5 0
3 years ago
Read 2 more answers
In the data set below, which of these points is most likely and outlier?
shusha [124]
<h2>Answer:</h2>

Option: D is the correct answer.

                 D.  (2,54)

<h2>Step-by-step explanation:</h2>

We know that an outlier of a data set is the value that stands out of the rest of the data point i.e. either it is a too high value or a too low value as compared to other data points.

Here  we are given a set of data points as:

         (2,54)

          (4,7)

         (6, 9)

         (8,12)

         (10,15)

Hence, we see that the output values i.e. 7 in (4,7) ; 9 in (6,9) ; 12 in (8,12) and 15 in (10,15) are closely related.

Hence, the data point that is an outlier is:

                  (2,54)

(As 54 is a much high value as compared to other)

5 0
3 years ago
What is the best first step in solving the equation 3x2 + 8x = -5?
Rashid [163]
I would assume it would be dividing both sides by three although if someone were to actually solve this I would say multiply 2 and 3 together first.

Hope this helps :)
5 0
3 years ago
A jar contains six blue marbles and five red marbles. Suppose you choose a marble at​ random, and do not replace it. Then you ch
TEA [102]

The jar has 6+5=11 marbles.

We have to find the probability of the following event:

1.We pick a marble from a jar that has 11 marbles in total, 5 of them are red

2.We pick a marble from a jar that has now 10 marbles in total, 4 of them are red (because in the previous step we picked a red marble and did not put it back in the jar)

The probability of the first event is:

P_1=\frac{5}{11}

The probability of the second event is:

P_2=\frac{4}{10}=\frac{2}{5}

The probability of the both events to happen is:

P=P_1\cdot P_2=\frac{5}{11}\cdot \frac{2}{5}=\frac{2}{11}=0.1818

3 0
3 years ago
Happy veterans day everybody!!!
Serjik [45]

Answer:

happy vets day

Step-by-step explanation:

4 0
3 years ago
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