Pythagorean theorem: a²+b²=c²
Where c = length of the hypotenuse (diagonal of a triangle)
60²+40²=c²
3600+1600=c²
5200=c²
c=√5200
c ≈ 72.11 ft
Answer:
Step-by-step explanation:
cartesian plane :
quadrant 1 : both x and y are positive
quadrant 2 : x is negative, y is positive
quadrant 3 : both x and y are negative
quadrant 4 : x is positive and y is negative
(-2,4)......we have x is negative and y is positive...so we are in quadrant 2
(3,-1)....we have x is positive and y is negative...in quadrant 4
(-1,0) ...if u have a 0 in ur points, they do not lie in any quadrant because they are located on an axis....this is located on axis x
(1,2)....both are positive....located in quadrant 1
(-3,-5)...both are negative.....quadrant 3
A linear equation of the form :
y = mx+b
can have at the most ONE x-intercept and at the most ONE y-intercept
I can conclude that this linear equation DOESN'T pass through the origin (O) and that it intercepts the x-axis as well as the y-axis
Answer:
Step-by-step explanation:
Question:
Prove the following statement directly from the definitions.
The difference of any two rational numbers is a rational number.
Answer, see attachment for proof.
620*1.35=837 so 837ml is the answer