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mart [117]
2 years ago
6

WILL GIVE BRAINLIEST! Find the equation of a line that passes through (-5,-2) and the intersection of the lines x+3y=0 and 4x-4y

-13=0
Mathematics
1 answer:
Verdich [7]2 years ago
6 0

Answer:

y + 2 = -0.069(x-+5)

Step-by-step explanation:

SInce the two lines intersects, we will equate it

Multiply x + 3y = 0 by 4;

4x + 12y = 0

4x-4y-13 = 0,

Subtracts both

12y +4y + 13 = 0

16y = 13

y = 13/16

get x;

x + 3(13/16) = 0

x = -39/16

The point of intersection is (0.8, -2.4) and (-5,-2)

Get the equation;

m = y2-y1/x2-x1

m = -2+2.4/-5-0.8

m = 0.4/-5.8

m = -0.069

Get the equation;

y - y0 = m(x-x0)

y - (-2)= -0.069(x-(-5))

y + 2 = -0.069(x-+5)

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Answer:

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Step-by-step explanation:

The additive identity of a set of number is a number such that the its sum with any of the numbers in the set would give a result that is equal to the number in that set.

In other words, say for example the set of numbers is rational, the additive identity of rational numbers is 0. This is because, given any rational number say <em>x</em>, adding zero to the number <em>x</em> gives the same number <em>x. </em>i.e

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<em></em>

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