WILL GIVE BRAINLIEST! Find the equation of a line that passes through (-5,-2) and the intersection of the lines x+3y=0 and 4x-4y
-13=0
1 answer:
Answer:
y + 2 = -0.069(x-+5)
Step-by-step explanation:
SInce the two lines intersects, we will equate it
Multiply x + 3y = 0 by 4;
4x + 12y = 0
4x-4y-13 = 0,
Subtracts both
12y +4y + 13 = 0
16y = 13
y = 13/16
get x;
x + 3(13/16) = 0
x = -39/16
The point of intersection is (0.8, -2.4) and (-5,-2)
Get the equation;
m = y2-y1/x2-x1
m = -2+2.4/-5-0.8
m = 0.4/-5.8
m = -0.069
Get the equation;
y - y0 = m(x-x0)
y - (-2)= -0.069(x-(-5))
y + 2 = -0.069(x-+5)
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