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mart [117]
3 years ago
6

WILL GIVE BRAINLIEST! Find the equation of a line that passes through (-5,-2) and the intersection of the lines x+3y=0 and 4x-4y

-13=0
Mathematics
1 answer:
Verdich [7]3 years ago
6 0

Answer:

y + 2 = -0.069(x-+5)

Step-by-step explanation:

SInce the two lines intersects, we will equate it

Multiply x + 3y = 0 by 4;

4x + 12y = 0

4x-4y-13 = 0,

Subtracts both

12y +4y + 13 = 0

16y = 13

y = 13/16

get x;

x + 3(13/16) = 0

x = -39/16

The point of intersection is (0.8, -2.4) and (-5,-2)

Get the equation;

m = y2-y1/x2-x1

m = -2+2.4/-5-0.8

m = 0.4/-5.8

m = -0.069

Get the equation;

y - y0 = m(x-x0)

y - (-2)= -0.069(x-(-5))

y + 2 = -0.069(x-+5)

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Answer:

The intermediate step are;

1) Separate the constants from the terms in x² and x

2) Divide the equation by the coefficient of x²

3) Add the constants that makes the expression in x² and x a perfect square and factorize the expression

Step-by-step explanation:

The function given in the question is 6·x² + 48·x + 207 = 15

The intermediate steps in the to express the given function in the form (x + a)² = b are found as follows;

6·x² + 48·x + 207 = 15

We get

1) Subtract 207 from both sides gives 6·x² + 48·x = 15 - 207 = -192

6·x² + 48·x = -192

2) Dividing by 6 x² + 8·x = -32

3) Add the constant that completes the square to both sides

x² + 8·x + 16 = -32 +16 = -16

x² + 8·x + 16 = -16

4) Factorize (x + 4)² = -16

5) Compare (x + 4)² = -16 which is in the form (x + a)² = b

7 0
3 years ago
What is the midpoint between -2-3i and 3+9i
Svetlanka [38]

Answer:

1/2 + 3i is the midpoint between -2-3i and 3+9i.

Step-by-step explanation:

Given the complex number

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The formula to find the midpoint of two complex number (a + bi) and (c + di) is:

M=\frac{\left(a+c\right)}{2}+\frac{\left(b+d\right)i}{2}

M=\frac{\left(-2+3\right)}{2}+\frac{\left(-3+\left(9\right)\right)i}{2}

M=\frac{-2+3+\left(-3+9\right)i}{2}

M=\frac{1+6i}{2}

M=\frac{1}{2}+3i

Therefore, 1/2 + 3i is the midpoint between -2-3i and 3+9i.

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