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mart [117]
3 years ago
6

WILL GIVE BRAINLIEST! Find the equation of a line that passes through (-5,-2) and the intersection of the lines x+3y=0 and 4x-4y

-13=0
Mathematics
1 answer:
Verdich [7]3 years ago
6 0

Answer:

y + 2 = -0.069(x-+5)

Step-by-step explanation:

SInce the two lines intersects, we will equate it

Multiply x + 3y = 0 by 4;

4x + 12y = 0

4x-4y-13 = 0,

Subtracts both

12y +4y + 13 = 0

16y = 13

y = 13/16

get x;

x + 3(13/16) = 0

x = -39/16

The point of intersection is (0.8, -2.4) and (-5,-2)

Get the equation;

m = y2-y1/x2-x1

m = -2+2.4/-5-0.8

m = 0.4/-5.8

m = -0.069

Get the equation;

y - y0 = m(x-x0)

y - (-2)= -0.069(x-(-5))

y + 2 = -0.069(x-+5)

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Water is added or drained from a tank each day. The first day, 910 of a gallon is added to the empty tank. The second day, 710 o
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Answer:

The quantity of water in the tank after 15 days is 1610.0 gallons OR 1.61 × 10³ gallons.

Step-by-step explanation:

The amount of water in the tank after 15 days is given by the series

910+(−710)+810+(−610)+⋯+310+(−110)+210

From the series, we can observe that, if water is added for a particular day then water will be drained the following day.

Also, for a day when water is to be added, the quantity to be added will be 100 gallon lesser than the quantity that was last added. Likewise, for a day when water is to be drained, the quantity to be drained will be 100 gallons lesser than the quantity that was last drained.

Hence, we can complete the series thus:

910+(−710)+810+(−610)+710(-510)+610(-410)+510(-310)+410(-210)+310+(−110)+210

To evaluate this, we  get

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Hence, the quantity of water in the tank after 15 days is 1610 gallons OR 1.61 × 10³ gallons.

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Step-by-step explanation:

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