Question

WILL GIVE BRAINLIEST! Find the equation of a line that passes through (-5,-2) and the intersection of the lines x+3y=0 and 4x-4y-13=0

Answer 1

Answer:

y + 2 = -0.069(x-+5)

Step-by-step explanation:

SInce the two lines intersects, we will equate it

Multiply x + 3y = 0 by 4;

4x + 12y = 0

4x-4y-13 = 0,

Subtracts both

12y +4y + 13 = 0

16y = 13

y = 13/16

get x;

x + 3(13/16) = 0

x = -39/16

The point of intersection is (0.8, -2.4) and (-5,-2)

Get the equation;

m = y2-y1/x2-x1

m = -2+2.4/-5-0.8

m = 0.4/-5.8

m = -0.069

Get the equation;

y - y0 = m(x-x0)

y - (-2)= -0.069(x-(-5))

y + 2 = -0.069(x-+5)