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Nady [450]
3 years ago
9

Find the value of x?!??????

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
3 0

Answer:

x = 31

Step-by-step explanation:

Given:

MN = 20

PQ = x

RS = 42

Required:

Value of x

SOLUTION:

In a trapezoid, the midsegment length equals the sum of both bases divided by 2

This implies that:

PQ = ½(MN + RS)

Plug in the values

x = ½(20 + 42)

x = ½(62)

x = 31

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M∠a=(48−x)°m∠b=(9x−38)°m∠c=90°
Fudgin [204]

Answer:

Option C:

  • m∠a = 38°
  • m∠b = 52°
  • m∠c = 90°

Step-by-step explanation:

Hello!

The sum of all angles in a triangle is 180°.

Add up all the angles and solve for x by setting the equation to 180°.

<h3>Solve for x</h3>
  • ∠a + ∠b + ∠c = 180°
  • (48 - x)° + (9x - 38)° + 90° = 180°
  • 10° + 8x + 90° = 180°
  • 8x = 180° - 90° - 10°
  • 8x = 80°
  • x = 10°

Now that we solved for x, we can plug it back into each equation to solve for each angle.

<h3>Angle A</h3>
  • 48° - x
  • 48° - 10°
  • 38°
<h3>Angle B</h3>
  • 9x - 38°
  • 9(10°) - 38°
  • 90° - 38°
  • 52°
<h3>Angle C</h3>
  • 90°

The answer is Option C:

  • m∠a = 38°
  • m∠b = 52°
  • m∠c = 90°
4 0
2 years ago
Consider the diagram. What is the length of segment AB?
Sloan [31]
B. 9 I think because it looks like it is bisected in the middle to cut into two equal parts. Please correct me if I am wrong. Thanks. 
4 0
3 years ago
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for employees of Papa Tony's pizza or cleaning up at the end of a busy night. There is a list of 43 complete a task that need to
nydimaria [60]
The answer is 10r3

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3 0
3 years ago
Who Goes To Markham Middle School? If so what teachers do you have??? :3
lesya692 [45]

Answer:

Vaush

Step-by-step explanation:

7 0
3 years ago
he pulse rates of 179 randomly selected adult males vary from a low of 43 bpm to a high of 115 bpm. Find the minimum sample size
malfutka [58]

Answer:

97

Step-by-step explanation:

Given that:

Low = 43bpm

High = 115 bpm

Error = 3

α = 90%

To find the range estimate :

Standard destviation = (high - low) / 4

Standard deviation = (115 - 43) / 4

Standard deviation = 72/4 = 18

The sample size,(n) :

n = [(Zα/2 * sd)/E] ²

2 - tail = (Zα/2) = 1.645

[(Zα/2 * sd)/E] ² = [(1.645 * 18) / 3]² = (29.61/3)²

= 97.41

Sample size = 97

5 0
3 years ago
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