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Aleksandr-060686 [28]
3 years ago
14

Which is not true 10 + 9 = 7 + 12 10 = 10 10 - 4 = 3 + 3 10 = 19 - 11

Mathematics
2 answers:
Novay_Z [31]3 years ago
7 0

Answer:

10= 19 - 11

Step-by-step explanation:

10+ 9= 19 and 7+12=19

10 is obviously equal to 10

10-4=6 and 3+3=6

But 10 is not equal to 19-11=8

Natasha2012 [34]3 years ago
3 0

Answer:

10=19-11

Step-by-step explanation:

that answer is false because 19-11 = 8 not 10

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Answer:

x=3

Step-by-step explanation:

2x-x=5-3+1

x=3

I think that's it

5 0
3 years ago
If yvaries inversely as x and y=18 when x=2, find y when x=4
Sergio039 [100]

I believe the answer would be 36.

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7 0
4 years ago
Please help 3(2x+1)+2(x+4)
Naya [18.7K]

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Step-by-step explanation:

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2 years ago
A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six
kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

V = Length \times Width \times Height \\\\

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

Width = 3 - 2x \\\\

The length of the shaded region is given by

Length = \frac{1}{2} (5 - 3x) \\\\

So, the volume of the box becomes,

V =  \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V =  \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V =  \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V =  \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

a = 18 \\\\b = -38 \\\\c = 15 \\\\

x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 +  19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\

Volume of the box at x= 1.59:

V =  \frac{1}{2} (5 – 3(1.59)) \times (3 - 2(1.59)) \times (1.59) \\\\V = -0.03 \: cm^3 \\\\

Volume of the box at x= 0.53:

V =  \frac{1}{2} (5 – 3(0.53)) \times (3 - 2(0.53)) \times (0.53) \\\\V = 1.75 \: cm^3

The volume of the box is maximized when x = 0.53 cm

Therefore,

x = 0.53 cm

Maximum volume = 1.75 cm³

7 0
3 years ago
The quotient of an unknown number and -13 is -14
zysi [14]

Answer:

182

Step-by-step explanation:

Quotient is division

Q/-13 = -14

Multiply each side by -13

Q/-13  * -13 = -14* -13

Q =182

The unknown number is 182

7 0
3 years ago
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