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MrMuchimi
3 years ago
11

(#4) which IS NOT a linear equation?

Mathematics
1 answer:
kifflom [539]3 years ago
8 0
The correct is g for your question
You might be interested in
Need help quick please thanks
Sloan [31]

Start by FOILing: First, Outer, Inner, Last.

3x•x= 3x^2; 3x•2= 6x; 2•x= 2x; 2•2= 4

Put it all together

3x^2 + 6x + 2x + 4

Combine like terms to get your answer

3x^2 + 8x + 4

8 0
3 years ago
Helppppp please my is on the line
s344n2d4d5 [400]

Answer:

i wanna say .05

Step-by-step explanation:

i did the two numbers divided then just rounded the decimal

3 0
3 years ago
A test has thirty questions worth 100 points. The test consists of True/False questions worth 3 points each and multiple choice
Vika [28.1K]
So let's break this question down.
You need a bit of both, right? Well we need to calculate how many multiple choices we can do whilst having true/false questions, and not going over or under on points.

So, let's pick a random number, 5. So let's do 8x5, that equals 40.
ohmygoditsrightiwasseriouslyjustguessing
Ok so now we have our number, 5 multiple choice questions. 
The true/false questions should be easy, just do 3x20 and you get 60.

ANSWER: 5 
5 0
3 years ago
Read 2 more answers
Suppose calls are arriving at a telephone exchange at an average rate of one per second, according to a Poisson arrival process.
antoniya [11.8K]

Answer:

Explanation has been given below

Step-by-step explanation:                    

a) inter arrival times are exponentially distributed with mean 1/n , where n = rate = 1/sec.                                                                              

  probability distribution function is F(t)=n*exp(-n*t).  

reference to any kth packet and the (k-1)th packet

the answer is = integration of F(t).dt with limits 0 to 2 = 1 - exp(-2*n) = 1 - exp(-2)  

b)  t=5 , P(q) = exp(-5)*(5)^q/factorial(q)  

probability of fourth call within t=5 seconds is =  

that is P(4)   P(5)   ......  = 1 - ( P(0)   P(1)   P(2)   P(3) ) ;  put the values and get the answer.  

c) number of calls/rate =  4/n = 4 seconds

5 0
3 years ago
Can someone help me draw this out to visualize it?
Vedmedyk [2.9K]

Answer:

Solution given:

South distance :base[b]=80milea

East distance :perpendicular [p]=35miles

Now

<S=?

we have

\tan( \alpha )  =  \frac{p}{b}  =  \frac{35 }{80}

\alpha  =  \tan {}^{ - 1} ( \frac{7}{16} )

\alpha  = 23.629°=24°

24° bearing should be taken from south airport to East airport.

3 0
3 years ago
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