All categories

3 years ago

Solve for x. 4(5x−20)=−20 NEED HELP ASAP

Mathematics

2 answers:

Allisa [31]3 years ago

4 0

4(5x-20)=-20
20x-80=-20
20x=60
x=3

torisob [31]3 years ago

4 0

Ok here is how you do it
4(5x-20)=-20
20x-80=-20
20x-80+80=60
20x=60
x=3

You might be interested in

Will give brainliest.

lesya692 [45]

Answer:

1. y = $\frac{-A}{By}$ x + $\frac{C}{By}$

2. Divide the Opposite of A and B

3. Doesn't make sense the y-intercept is C/By sry I can't help that one

Step-by-step explanation:

1. Ax + By = C

By = -Ax + C

y = $\frac{-A}{By}$ x + $\frac{C}{By}$

2. No explanation

3 0

2 years ago

4x-3 (x-2y) + 1/2 (6x-8y)

Neporo4naja [7]

4x+2y i hope that helps :3

6 0

2 years ago

Read 2 more answers

30+ Points!!!<br> 5. Solve the following inequalities.<br> a) 2 log3x – 2 logx3 -3 <0

Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

$\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}$

$2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)$

$\mathrm{Simplify}$

$-2logx^3-3$

$\mathrm{Add\:}3\mathrm{\:to\:both\:sides}$

$-2logx^3-3+3$

$\mathrm{Simplify}$

$-2logx^3$

$Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)$

$\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)$

$\mathrm{Simplify}$

$2lx^3og>2\log ^3\left(x\right)-3$

$\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0$

$\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\$

$\mathrm{Simplify}$

$g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0$

Step-by-step explanation:

6 0

3 years ago

2000x100 guesss yall

Svet_ta [14]

Answer:

200,000

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Solve system of equations 2x + 2y + 5z = 7 6x + 8y + 5z = 9 2x + 3y + 5z = 6

svet-max [94.6K]

Answer:

the values of x, y and z are x= 2, y =-1 and z=1

Step-by-step explanation:

We need to solve the following system of equations.

We will use elimination method to solve these equations and find the values of x, y and z.

2x + 2y + 5z = 7 eq(1)

6x + 8y + 5z = 9 eq(2)

2x + 3y + 5z = 6 eq(3)

Subtracting eq(1) and eq(3)

2x + 2y + 5z = 7

2x + 3y + 5z = 6

- - - -

_____________

0 -y + 0 = 1

-y = 1

=> y = -1

Subtracting eq(2) and eq(3)

6x + 8y + 5z = 9

2x + 3y + 5z = 6

- - - -

______________

4x + 5y +0z = 3

4x + 5y = 3 eq(4)

Putting value of y = -1 in equation 4

4x + 5y = 3

4x + 5(-1) = 3

4x -5 = 3

4x = 3+5

4x = 8

x= 8/4

x = 2

Putting value of x=2 and y=-1 in eq(1)

2x + 2y + 5z = 7

2(2) + 2(-1) + 5z = 7

4 -2 + 5z = 7

2 + 5z = 7

5z = 7 -2

5z = 5

z = 5/5

z = 1

So, the values of x, y and z are x= 2, y =-1 and z=1

5 0

3 years ago

Solve for x. ​ 4(5x−20)=−20 ​NEED HELP ASAP

Solve for x. 4(5x−20)=−20 NEED HELP ASAP