Answer=7:13
Kenny's Weight*6/7=Melvin's Weight
So, for example, if Melvin's weigh was 7...
Kenny's Weight*6/7=7
divide both sides by 6/7
Kenny Weight=6
So we can say that Melvin's weight to Kenny's weight is 7:6
The boys total weights would be...
7+6=13
So Melvin's weight over the total weight of the two boys is:
7:13
Since the word, 'of' means to multiply, whenever we see of multply the two numbers.
Then there are two ways to dothis, sicne to convert a percentage into a decimal, you devide by 100, we can either do this after we multiply or bfore, it doesn't matter so I'm going to do it after.
1. 520x100=52000/100=520
2. 20.25x3=60.75/100=.6075
3. .15x250=37.5/100=.375
4. 200x79=15800/100=158
5..3x80=24/100=.24
6. .28x50=14/100=.14
Our P = 100, r = .08, n = 1 (annually means once a year), and t = 15. Filling in accordingly, we have
. Simplifying a bit gives us
and
. Raising that number inside the parenthesis to the 15th power gives us
. Multiplying to finish means that A(t) = $317.22
The answer is 5.13 in²
Step 1. Calculate the diameter of the circle (d).
Step 2. Calculate the radius of the circle (r).
Step 3. Calculate the area of the circle (A1).
Step 4. Calculate the area of the square (A2).
Step 5. Calculate the difference between two areas (A1 - A2) and divide it by 4 (because there are total 4 segments) to get <span>the area of one segment formed by a square with sides of 6" inscribed in a circle.
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Step 1:
The diameter (d) of the circle is actually the diagonal (D) of the square inscribed in the circle. The diagonal (D) of the square with side a is:
D = a√2 (ratio of 1:1:√2 means side a : side a : diagonal D = 1 : 1 : √2)
If a = 6 in, then D = 6√2 in.
d = D = 6√2 in
Step 2.
The radius (r) of the circle is half of its diameter (d):
r = d/2 = 6√2 / 2 = 3√2 in
Step 3.
The area of the circle (A1) is:
A = π * r²
A = 3.14 * (3√2)² = 3.14 * 3² * (√2)² = 3.14 * 9 * 2 = 56.52 in²
Step 4.
The area of the square (A2) is:
A2 = a²
A2 = 6² = 36 in²
Step 5:
(A1 - A2)/4 = (56.52 - 36)/4 = 20.52/4 = 5.13 in²
Y= -x and y= -1/x
Are one-one
y= -x, inverse x= -y
Identify function
hence, inverse of y= -x in y= -x
similarly in the case of y= -1/x
so option (D) I and II, only
