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2 years ago

Help me please again lol :> here's a picture

Mathematics

2 answers:

Pani-rosa [81]2 years ago

5 0

They only have the same perimeter, to find perimeter you add up all the sides, and to fine area you do length x height

Delvig [45]2 years ago

4 0

Answer:

It's Same perimeter only

Step-by-step explanation:

It can't be the other two because they don't share the same area

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Answer:

Mean = 33.31

Median = 26

Mode = 17

Step-by-step explanation:

Given the data:

32 44 25 66 27 12 62 9 51 4 17 50 35 99 30 21 12 53 25 2 18 24 84 30 17 17

Reordered data : 2, 4, 9, 12, 12, 17, 17, 17, 18, 21, 24, 25, 25, 27, 30, 30, 32, 35, 44, 50, 51, 53, 62, 66, 84, 99

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3 years ago

The perimeter of a rectangular fence is to be at least 120 feet and no more than 168 feet. If the length of the fence is to be t

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A rectangle has a perimeter of length + length + width + width.

L = length of the fence.

W = width of the fence.

so the perimeter will be L+L+W+W or 2L+2W or 2(L+W).

now, we know that 120 ⩽ 2(L+W).

we also know that 168 ⩾ 2(L+W)

and we also know that whatever the length is, is twice the width, or L = 2W.

$\bf 120\le 2(L+W)\implies 120\le 2(2W+W)\implies 120\le 2(3W)
\\\\\\
120\le 6W\implies \cfrac{120}{6}\le W\implies \boxed{20\le W}\\\\
-------------------------------\\\\
168\ge 2(L+W)\implies 168\ge 2(2W+W)\implies 168\ge 2(3W)
\\\\\\
168\ge 6W\implies \cfrac{168}{6}\ge W\implies \boxed{28\ge W}\\\\
-------------------------------\\\\
20\le W \le 28$

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