Answer:
What is the real meaning of this questions
I think the glycolysis occurs in the cytosol.
Answer:
Alfred Lothar Wegener was a German polar researcher, geophysicist and meteorologist. During his lifetime he was primarily known for his achievements in meteorology and as a pioneer of polar research.
You can do golden rice. It was genetically modified to produce beta carotene, which rice does not usually have. When metabolized by the body beta carotene is turned to vitamin A which is essential to human vision, immune systems, and healthier skin
Answer:
a. 8.1 milligrams
b. 40.07 hours
c. 8.859 milligrams
Explanation:
If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time can be modeled by
![A_{t}=10e^{-0.0173t}](https://tex.z-dn.net/?f=A_%7Bt%7D%3D10e%5E%7B-0.0173t%7D)
Where A(t) = amount of Valium remaining in the blood after t hours
t = time or duration after the drug is taken
a. we have to calculate the amount of drug remaining in the bloodstream after 12 hours
![A_{12}=10e^{-0.0173\times12}](https://tex.z-dn.net/?f=A_%7B12%7D%3D10e%5E%7B-0.0173%5Ctimes12%7D)
![A_{12}=10e^{-0.2076}](https://tex.z-dn.net/?f=A_%7B12%7D%3D10e%5E%7B-0.2076%7D)
= 10×0.81253
= 8.1 milligrams
b. In this part we have to calculate the time when A(t) = 5 milligrams
![5=10e^{-0.0173\timest}](https://tex.z-dn.net/?f=5%3D10e%5E%7B-0.0173%5Ctimest%7D)
![\frac{5}{10}=e^{-0.0173t}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B10%7D%3De%5E%7B-0.0173t%7D)
0.5 = ![e^{-0.0173t}](https://tex.z-dn.net/?f=e%5E%7B-0.0173t%7D)
Now we take natural log on both the sides of the equation.
ln(0.5) = ln(![e^{-0.0173t})](https://tex.z-dn.net/?f=e%5E%7B-0.0173t%7D%29)
-0.69314 = -0.0173t
t = ![\frac{0.69314}{0.0173}](https://tex.z-dn.net/?f=%5Cfrac%7B0.69314%7D%7B0.0173%7D)
t = 40.0658
≈ 40.07 hours
c. In this part we have to calculate the rate, by which amount of drug will decay in the bloodstream after 7 hours.
![A_{7}=10e^{-0.0173\times7}](https://tex.z-dn.net/?f=A_%7B7%7D%3D10e%5E%7B-0.0173%5Ctimes7%7D)
![A_{7}=10e^{-0.1211}](https://tex.z-dn.net/?f=A_%7B7%7D%3D10e%5E%7B-0.1211%7D)
= 10×0.8859
= 8.859 milligrams