a. Miss Butler made a circle graph to show the grades on the term papers. There were 14 B's, 10 A's, and 8 C's.

Find the mean median range and mode for 3, 3, 4, 8, 9, 10, and 12

Alexeev081 [22]

Answer:

Mean: 7

Median: 8

Range: 9

Mode: 3

Step-by-step explanation:

First, to find the mean of a set of numbers you need to add up all of the numbers and divide that by the total amount of numbers. In this case that makes this equation, $\frac{3+3+4+8+9+10+12}{7}$ , which is $\frac{49}{7}$ , which is 7.

To find a median you need to find the middle number. A handy trick I use for this is to place my fingers on the first and last number, and then move them towards the middle, at the same time by one number until there is just one number left in the middle. If there are no numbers left after doing this, meaning there are an even amount of numbers given, the median is the mean of the last two numbers that were covered. In this case, this is not necessary, so the median is 8.

The range is the difference between the maximum and minimum of a data set. In this case that would give you the equation Range=12-3, which means the range is 9.

Finally, the mode is the number that occurs the most in a given data set. In this case the number that occurs the most is 3, which occurs twice compared to every other number which only occurs once.

5 0

3 years ago

Read 2 more answers

Solve for a<img src="https://tex.z-dn.net/?f=S%20%3D%20%5Cfrac%7Bn%7D%7B2%7D%20%28a%2Bl%29" id="TexFormula1" title="S = \frac{n}

slavikrds [6]

Answer:

The answer is

$\frac{2s}{n} - l = a$

Step-by-step explanation:

$s = \frac{n}{2} (a + l)$

multiply both sides by 2 to get

$2s = n(a + l)$

divide both sides by n to get

$\frac{2s}{n} = a + l$

subtract L from both sides to get the answer

$\frac{2s}{n} - l = a$

6 0

3 years ago

What is this expression in the simplest radical form

Ede4ka [16]

Fist you would distribute then simplify the radical.

8 0

4 years ago

The school is having a bake sale and the math club is bringing cupcakes. They have 180 total cupcakes, both chocolate and strawb

jeka57 [31]

Let $s$ be the number of strawberry cupcakes, and $c$ the number of chocolate cupcakes.
From our problem we know that the total number of cupcakes is 180, so $c+s=180$ . We also know that the number of chocolate cupcakes is eighteen more than twice the number of strawberry cupcakes, so $c-18=2s$ , or solving for $c$ : $c=2s+18$ .
Know we have our system of equations:
$\left \{ {{c+s=180} \atop {c=2s+18}} \right.$
We can conclude that the correct answer is B. c + s = 180 c = 2s + 18.

Lets solve our equations to find how many cupcakes of each they have:
from our second equation we know that $c=2s+18$ ; lets replace that value in our first equation to find the number of strawberry cupcakes:
$2s+18+2=180$
$3s=162$
$s= \frac{162}{3}$
$s=54$
Now that we know the number of strawberry cupcakes, lets replace that value in our second equation to find the number of chocolate cupcakes:
 $c=2(54)+18$
$c=108+18$
$c=126$
As a bonus, we can conclude that the math club have 126 chocolate cupcakes and 54 strawberry cupcakes.

8 0

3 years ago

Read 2 more answers

2.05×5 with shown work

poizon [28]

Answer:

10.25

Step-by-step explanation:

205 × 5 = 1025

2.05 has 2 decimal places

5 has 0 decimal places

Therefore, the answer has 2 decimal places

1025

10.25

6 0

3 years ago

a. Miss Butler made a circle graph to show the grades on the term papers. There were 14 B's, 10 A's, and 8 C's.​

a. Miss Butler made a circle graph to show the grades on the term papers. There were 14 B's, 10 A's, and 8 C's.