a. Miss Butler made a circle graph to show the grades on the term papers. There were 14 B's, 10 A's, and 8 C's.
1 answer:
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Slope-intercept form:
y = mx + b "m" is the slope, "b" is the y-intercept (the y value when x = 0)
First find the slope of the line that passes through (4,9) and (-3,6).
Use the slope formula and plug in the two points:
A.) For lines to be parallel, their slopes have to be the same.
Since the given line's slope is 3/7, the parallel line's slope is also 3/7
y = 3/7x + b To find "b", plug in the point (14,8) into the equation
8 = 3/7(14) + b
8 = 42/7 + b
8 = 6 + b Subtract 6 on both sides
2 = b
B.) For lines to be perpendicular, their slopes have to be the opposite/negative reciprocal (flipped sign and number)
For example:
slope is 3
perpendicular line's slope is -1/3
slope is -2/3
perpendicular line's slope is 3/2
Since the given line's slope is 3/7, the perpendicular line's slope is -7/3
y = -7/3x + b Plug in (14, 8) to find "b"
8 = -7/3(14) + b
8 = -98/3 + b Add 98/3 on both sides
8 + 98/3 = b Make the denominators the same
24/3 + 98/3 = b
122/3 = b
Answer:
Realization :
since there are 3-variable. Therefore 2ⁿ = 2³ = 8
From the attached solution, f(x,y,z) = y' + xz'
also' see the circuit diagrams of my realizations of AND-OR and NAND-NAND
Step-by-step explanation:
See attached picture for minimal 2-level AND-OR and NAND-NAND of the logic function.
f(x,y,z) = y' + xz' was designed from the function f(x,y,z) = Σm(0,1,4,5,6)
Then, minimal 2-level AND-OR was designed and after was NAND-NAND designed as well.
