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marishachu [46]
3 years ago
15

Are the triangles similar? Explain how you know.

Mathematics
2 answers:
just olya [345]3 years ago
7 0

Answer: Yes,these triangles are similar because they are both obtuse, scalene, and they both have three sides

MissTica3 years ago
4 0
Can’t see the numbers
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The daily temperatures in fall and winter months in Virginia have a mean of 62°F. A meteorologist in southwest
marshall27 [118]

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,, assuming the true mean temperature 62 degrees Fahrenheit there is a 0.1% probability that the null hypothesis is true by chance alone

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7. If the longer leg of a right triangle is twice as long as the shorter leg, what is the ratio of
kicyunya [14]

Answer: The ratio is 2.39, which means that the larger acute angle is 2.39 times the smaller acute angle.

Step-by-step explanation:

I suppose that the "legs" of a triangle rectangle are the cathati.

if L is the length of the shorter leg, 2*L is the length of the longest leg.

Now you can remember the relation:

Tan(a) = (opposite cathetus)/(adjacent cathetus)

Then there is one acute angle calculated as:

Tan(θ)  =  (shorter leg)/(longer leg)

Tan(φ) = (longer leg)/(shorter leg)

And we want to find the ratio between the measure of the larger acute angle and the smaller acute angle.

Then we need to find θ and φ.

Tan(θ) = L/(2*L)

Tan(θ) = 1/2

θ = Atan(1/2) = 26.57°

Tan(φ) = (2*L)/L

Tan(φ) = 2

φ = Atan(2) = 63.43°

Then the ratio between the larger acute angle and the smaller acute angle is:

R = (63.43°)/(26.57°) = 2.39

This means that the larger acute angle is 2.39 times the smaller acute angle.

5 0
3 years ago
Find the total thickness of two pieces of wood that a carpenter glued together if one is 5/16 inches and the other is 7/8 inches
konstantin123 [22]
The answer is 1 3/16 inches
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Looking for the answer to this
SashulF [63]
<h2><u>Requi</u><u>red</u><u> Answer</u><u> </u><u>:</u><u>-</u></h2>

Given system of linear equations are ,

  • x + y = 2
  • -3x + y = 2

And we need to find the Solution of the linear equation . So let's Firstly number the equations .

\large{\red{\frak{ Given}}}\begin{cases} \sf x + y = 2\qquad ..........(i) \\\\\sf -3x + y = 2 \qquad ..........(ii) \\\end{cases}

<u>→</u><u> </u><u>Multipl</u><u>ying</u><u> </u><u>equⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>by</u><u> </u><u>3</u><u> </u><u>,</u>

=> 3 ( x + y ) = 2*3

=> 3x + 3y = 6

<u>→</u><u> </u><u>Addin</u><u>g</u><u> </u><u>the</u><u> </u><u>two</u><u> </u><u>equations </u><u>,</u><u> </u>

=> 3x + 3y -3y + y = 6 + 2

=> 4y = 8

=> y = 8/4

=> y = 2

<u>→</u><u> </u><u>Put</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>in</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>,</u>

=> x + y = 2

=> x + 2 = 2

=> x = 2- 2

=> x = 0

<h3><u>★</u><u> </u><u>Hence</u><u> the required solution is ( 0 , 2 ) .</u></h3>
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You are asked to run two wires. The total length of the wires is 16m. One of the wires needs
Elenna [48]
One wire is 8.5m, and the other wire is 7.5m.
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