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3 years ago

HEY could some please help me out !!!!!!

Mathematics

2 answers:

zhenek [66]3 years ago

6 0

The first one is the correct answer

Zina [86]3 years ago

4 0

First one is the correct cause it has a pattern

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Clint spends 1/2 hour practicing trumpet, 3/4 hour doing tasks around the house, 1 1/2 hour doing homework, and 1/4 hour cleanin

AfilCa [17]

4:30 PM! Because you have to add up all the time he spent doing these activities which is 3 hours and what time is three hours before 7:30? The answer is 4:30! Hope this helps!

8 0

4 years ago

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QUICK: find the equation of the quadratic function with a zero of -4 and a vertex at (-1,-8) express your answer in standard for

garik1379 [7]

Answer:

-4.05

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

I'm so bad at math please anyone help :(

kondaur [170]

It should be d. , Because if you take the equation 3x+y=9, and make it slope intercept form, it would be y= -3x+9. -3 is the slope, and 9 is the y intercept. D is the answer.

6 0

3 years ago

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

4 years ago

I’m confused help me i need it rn

Likurg_2 [28]

Answer:

y = -(2/5)x+4

Step-by-step explanation:

The 2 points are 0,4 and 5,2. If you want to find the equation, you need slope. slope = rise/run = -2/5.

y = mx + b. The b is the y intercept, so it's 4.

The equation is y = -(2/5)x+4

7 0

3 years ago