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abruzzese [7]
2 years ago
7

How do you solve this 21 = 14 + 7x

Mathematics
1 answer:
pav-90 [236]2 years ago
7 0

Answer:

subtract 14 from each side

7=7x

x=1

Step-by-step explanation:

plz brainliest!

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The sum of four consecutive integers is at least 18. What's the smallest consecutive integer to make this statement true?
Ghella [55]

Let the four consecutive integers be

x , x+1, x+2, x+3

ATQ, Their sum is 18

\sf \: x + x + 1 + x + 2 + x + 3 = 18

\sf \: 4x + 1 + 2 + 3 = 18

\sf4x + 6 = 18

\sf4x = 18 - 6

\sf4x = 12

\boxed{ \mathfrak{x = 3}}

<h3>Now,</h3>

  • 1st number = x = 3
  • 2nd number = x+1 = 3+1 = 4
  • 3rd number = x+2 = 3+2 = 5
  • 4th number = x+3 = 3+3 = 6

<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>

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3 years ago
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lakkis [162]
The correct option would be C
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3 years ago
A truck that is 10 ft. by 12 ft. by 8 ft. carries cube shaped boxes that have a
dedylja [7]

Answer:

284.4

Step-by-step explanation:

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The width of a rectangle is 5 units less than the length. The area of the rectangle is 6 units. What is the width, in units, of
Readme [11.4K]

Answer:

The width of rectangle is 1 unit.

Step-by-step explanation:

Given:

The area of rectangle is 6 units and its width is 5 units less than the length.

So, to find the width of rectangle.

Let the length be x and the width be x-5.

Now, to find the width we put the formula of area of rectangle:

Area = length × width

6= x\times (x-5)

6=x^{2}-5x

0=x^{2}-5x-6

0=x^{2}-6x+x-6

0=x(x-6)+1(x-6)

0=(x-6)(x+1)

<em>On solving equation we get:</em>

x-6=0, x+1=0

Therefore, we take the value x=6 as it is positive value:

x-6=0

x=6

So, the width of rectangle:

Width = x-5

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Therefore, the width of rectangle is 1 unit.

8 0
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