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3 years ago

What terms can be combined with 3a? Select all that apply.

Mathematics

2 answers:

antiseptic1488 [7]3 years ago

6 0

Answer:

You can only add like terms with like terms, so the terms that can be combined with 3a are the terms that end in an a.

So, the answers are:

4a and 14a

Let me know if this helps!

viva [34]3 years ago

3 0

Answer:

4a and 14a

Let me know if this helps!

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Gelneren [198K]

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2 years ago

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Describe the steps in solving the linear equation 3(3x − 8) = 4x + 6.

Fittoniya [83]

Answer:

x=6

Step-by-step explanation:

3(3x-8)=4x+6

First you would distribute the 3 on the L side to the parenthasies

9x-24=4x+6

Then, you would subtract 4x from both sides because it is the smallest X value

5x-24=6

Add 24 to both sides (inverse operations)

5x=30

divide both sides by 5

x=6

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3 years ago

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To eliminate the y-terms and solve for x in the fewest steps, by which constants should the equations be multiplied by before ad

vovikov84 [41]

Answer:

use -9 to multiply the first equation

use -4 to multiply the second equation.

Step-by-step explanation:

5x-4y=28.....eqn (1)×-9

3x-9y=30....eqn(2)×-4

-45x+36y=-252

-(-12x+36y=-120)

therefore, -33x÷33 =-132÷-33

x=4.

substitute (x=4) in any of the equation. I'm just going to use eqn 1.

5x-4y=28

5(4)-4y=28

20-4y=28

-4y =28-20

-4y÷-4 = 8÷-4

y=-2

so, x=4, y=-2

Note: for proof of answers substitute the answers for x and y and see if you have the same result...e.g

5(4)-4(-2)=28.

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3 years ago

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Find the domain of the relation R = {(4, 5), (6, 7), (8, 9)}

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3 years ago

arthur wants to buy an item that costs p dollars before tax. using a 6% sales tax rate, write two different expressions that rep

Mkey [24]

For this case we have the following variable:

p: cost of the item that Arthur wants to buy before tax

The expression for the 6% tax is given by:

$\frac{6}{100} p$

Or equivalently:

$0.06p$

Therefore, two different expressions for the total cost are:

Expression 1:

$p + \frac{6}{100} p$

Expression 2:

$p + 0.06p$

To prove that they are equal, suppose that the item costs $ 100:

Expression 1:

$p + \frac{6}{100} p$

$100+ \frac{6}{100} 100$

$100 + 6$

$106$

Expression 2:

$p + 0.06p$

$100 + 0.06 (100)$

$100 + 6$

$106$

Since the cost is the same, then the expressions are the same.

Answer:

Two different expressions that model the problem are:

$p + \frac{6}{100} p$

$p + 0.06p$

8 0

3 years ago