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Andru [333]
3 years ago
6

I need help pleaseeeee!!

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

option 4

Step-by-step explanation:

fog(x)=(x-5)²+4

=x²-10x+25+4

fog(x)=x²-10x+29

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Find the coordinates of B' after a reflection across the x-axis. show your work​
bazaltina [42]

Answer:

  • B'(8, 6)

Step-by-step explanation:

Coordinates of point B = (8, -6)

<u>Reflection across the x-axis results in:</u>

  • (x, y) → (x, -y)

<u>Coordinates of B'</u>

  • (8, -6) → (8, -(-6)) = (8, 6)
8 0
3 years ago
Hey can you help me out? You don’t have to show your work, just the answer!
Volgvan

Answer: you are correct for every choice

4 0
3 years ago
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Help please hurry!!!!!!!!!!!!!!!!!!!!!!!!! What is a correct name for the angle shown?
Pavlova-9 [17]

Answer:

Angle RTS

Step-by-step explanation

Say it out loud it goes, RS, ST.

If you put RS and ST together the angle RTS

3 0
3 years ago
What is the translation from quadrilateral IJK to<br> quadrilateral I'J’K’
liberstina [14]

Answer:

The translation from triangle IJK to triangle I'J'K' is T_{(2, 6)} which is 2 units to the right and 6 units up

Step-by-step explanation:

The coordinates of triangle JKI are;

J has coordinates (1, - 1)

K has coordinates (1, - 4)

I has coordinates (-3, - 2)

While, the coordinates of translation triangle J'K'I' are;

J' has coordinates (3, 5)

K' has coordinates (3, 2)

I' has coordinates (-1, 4)

Which give the translation as follows

Translation in the y-coordinate (y values);

For J = 5 - (-1) = 6

For K = 2 - (-4) = 6

For I = 4 - (-2) = 6

Translation in the x-coordinate (x values);

For J = 3 - 1 = 2

Therefore, the translation from triangle IJK to triangle I'J'K' is T(2, 6) which is 2 units to the right and 6 units up

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Ede4ka [16]

Answer:

the answer is A.

Step-by-step explanation:

7 0
3 years ago
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