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Ainat [17]
3 years ago
12

5 (RootIndex 3 StartRoot x EndRoot) + 9 (RootIndex 3 StartRoot x EndRoot)

Mathematics
1 answer:
Ratling [72]3 years ago
8 0

Answer:

C. 14 RootIndex 3 StartRoot x EndRoot)

Step-by-step explanation:

To obtain the sum ; the a clear explanation has been attached in the picture below ;

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Answer:

URGENT

Debug the following:any one free out

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8 0
2 years ago
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The area of a rectangle is 44 square feet. The base of the rectangle is 11. Find the height, then find the perimeter
Alecsey [184]

Answer:

4

Step-by-step explanation:

Since the area of a rectangle = Length times Breath

We are just going to divide your are by breadth which is

Let your length become y

= y × 11 = 44

to get your answer you move× 11 over the equal to sign which becomes ÷11 because any sign that cross the equal to sign changes which is equal to

y = 44÷11

y = 4

what i did was that i divided 44 by 11 which is equal to 4

3 0
3 years ago
PLease see the picture below please help me thank you.
Mama L [17]

3r +8

combine 4r -r

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3r + 8

5 0
2 years ago
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Which transformations could be performed to show that △ABC is similar to △A"B"C"?
Angelina_Jolie [31]

Answer:

A 180° rotation of then a dilation by a scale factor of one-third

Step-by-step explanation:

The coordinates of the vertices of ΔABC are;

A(-9, 3), B(-9, 6), and C(0, 3)

The coordinates of the vertices of ΔA'B'C' are;

A'(3, -1), B'(3, -2), and C'(0, -1)

We note that for a 180° rotation transformation about the origin, we get;

Coordinates of preimage = (x, y)

Coordinates of image after 180° rotation about the origin = (-x, -y)

Therefore, a 180° rotation of ΔABC about the origin, would give ΔA''B''C'' as follows;

A(-9, 3), B(-9, 6), and C(0, 3) = A''(9, -3), B''(9, -6), and C''(0, -3)

The formula for a dilation of a point about the origin is given as follows;

D_{O, \, k} (x, \, y) = (k\cdot x, \, k\cdot y)

Where;

k =The scale factor = 1/3, (one-third) we have;

A dilation of ΔA''B''C'', by a scale factor of 1/3, we get ΔA'B'C' as follows;

D_{O, \, \frac{1}{3} } A''(9, \, -3) = A'(\frac{1}{3} \times 9, \, \frac{1}{3} \times -3) = A'(3, -1)

D_{O, \, \frac{1}{3} } B''(9, \, -6) = B'(\frac{1}{3} \times 9, \, \frac{1}{3} \times -6) = A'(3, -2)

D_{O, \, \frac{1}{3} } C''(0, \, -3) = C'(\frac{1}{3} \times 0, \, \frac{1}{3} \times -3) = C'(0, -1)

The coordinates of the vertices of ΔA'B'C' are A'(3, -1), B'(3, -2), and C'(0, -1), which is the same as the required coordinates of the image;

Therefore, the transformation that can be performed to show that ΔABC and ΔA'B'C' are similar are rotating ΔABC by 180°  then a dilating the image derived after rotation by a scale factor of one-third (1/3) we get ΔA'B'C'.

7 0
2 years ago
How can x2 = x2 + 2x + 9 be set up as a system of equations?
Andreas93 [3]
X2 = x2 + 2x + 9   Now subtract x2 from both sides and you have

x2- x2 = x2 - x2 + 2x + 9  or  0 = 2x + 9  now subtract 9 from both sides so you can solve for x.

0 -9 = 2x -9...and you have -9 = 2x 

Now solve for x  by dividing both sides by 2 and you arrive at x = -4.5
3 0
3 years ago
Read 2 more answers
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