<u>Note: The only way to solve this problem is by adjusting the fees to $3.50 and $7.50.</u>
Answer:
<em>1300 children attended the basketball game</em>
Step-by-step explanation:
System of Equations
Let's call:
x = number of children attending the basketball game
y = number of adults attending the basketball game
On a certain night, 1500 people enter the game, thus:
x + y = 1500 [1]
Since each admission fee for children cost $3.50 and $7.50 for adults and it was collected $6050, thus:
3.50x + 7.50y = 6050 [2]
From [1]:
y = 1500 - x
Substituting in [2]:
3.50x + 7.50(1500 - x) = 6050
Operating:
3.50x + 11250 - 7.50 = 6050
-4x = 6050 - 11250
Solving:
x = 1300
1300 children attended the basketball game
((-4)^5)^8 / ((-4)^7)^3
= (-4)^40 / (-4)^21
= (-4)^20
(3,59)(5,87)
slope = (87 - 59) / (5 - 3) = 28/2 = 14 <== ur slope
y = mx + b
slope(m) = 14
use either of ur points...(3,59)...x = 3 and y = 59
now we sub and find b, the y int
59 = 14(3) + b
59 = 42 + b
59 - 42 = b
17 = b <=== ur y int (0,17)
---------------------
given:
= cost of Brazilian coffee in mixture
= cost of Venezuelan coffee in mixture
= cost of mixture
---------------------
Now I can rite these equations:
(1)
(2)
Multiply both sides of (2) by and
subtract from (1)
(1)
(2)
and, since
288 kg of Brazilian coffee and 96 kg of Venezuelan coffee are needed
