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3 years ago

Estimate the quotient for: 4,819÷68

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

6 0

Answer:

≈ 70.87 (rounded to the nearest hundredth)

Step-by-step explanation:

-When you do 4,819 ÷ 68, you’ll get:

70.867647058....

-So, just round it to the nearest hundredth:

70.87

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A 9,000-lb load is suspended from the roof in a shopping mall with a 16-ft-long solid aluminum rod. The modulus of elasticity of

Westkost [7]

Answer:

Step-by-step explanation:

Given:

elongation, x = 0.50 in

Force, f = 9000 lb

Young modulus, E = 10,000,000 psi

Maximum Stress, Sm = 30000 psi

Length, L = 16 ft

Converting ft to in,

12 in = 1 ft

=16 × 12 = 192 in

Young modulus, E = stress/strain

Stress = force/area, A

Strain = elongation, x/Length, L

E = f × L/A × E

1 × 10^7 = stress/(0.5/16)

= 26041.7 psi

Minimum stress = 26041.7 psi

Maximum stress = 30,000 psi

Stress = force/area

Area = 9000/26041.7

= 0.3456 in^2

Stress = force/area

Area = 9000/30000

= 0.3 in^2

Using minimum area of 0.3 in^2,

A = (pi/4)(d^2)

0.3 in^2 = (pi/4)(d^2)

d = 0.618 inches

diameter, d = 0.618 inches

7 0

3 years ago

Match each expression written in standard form to the equivalent expression in factored form

den301095 [7]

Answer:

1. 15x^7y^2 + 4x^3 => x^3(15x^4y^2 + 4)

2. 15x^7y^2 + 3x => 3x(5x^6y^2 + 1)

3. 15x^7y^2 + 6xy => 3xy(5x^6y + 2)

4. 15x^7 + 10y^2 => 5(3x^7 + 2y^2)

Step-by-step explanation:

To obtain the answer to the question, first let us factorise each expression. This is illustrated below:

1. 15x^7y^2 + 4x^3

Common factor is x^3, therefore the expression is written as:

x^3(15x^4y^2 + 4)

2. 15x^7y^2 + 3x

Common factor is 3x, therefore the expression is written as:

3x(5x^6y^2 + 1)

3. 15x^7y^2 + 6xy

Common factor is 3xy, therefore the expression is written as:

3xy(5x^6y + 2)

4. 15x^7 + 10y^2

Common factor is 5, therefore the expression can be written as:

5(3x^7 + 2y^2)

4 0

3 years ago

I am so confused how am I supposed to do this

solniwko [45]

Rise over run, -2/4 or -1/2 so the slope is -1/2 or -0.5. (View picture) And the slope is negative because you are going down wards \ and the "rise" is going down.

6 0

3 years ago

Read 2 more answers

Write a function rule for the table.

pashok25 [27]

Answer:

it will be the last one bc 18d is on the chart

7 0

2 years ago

Read 2 more answers

Tublu buys a cylindrical water tank of height 1.4m and diameter 1.1m to catch rainwater off his roof. He has a full 2 litres tin

vesna_86 [32]

Answer:

Yes, he will have enough paint to cover the tank with one layer of paint.

Step-by-step explanation:

We are given that Tublu buys a cylindrical water tank of height 1.4 m and diameter 1.1 m to catch rainwater off his roof. He has a full 2 liters tin of paint in his store and decides to paint the tank (not the base).

He uses 250 ml to cover 1 $\text{m}^{2}$ .

From the question, it is clear the area of the tank which needs to be painted is the lateral surface area (because the base is not included).

The lateral surface area of the cylinder = $2\pi rh$

where, r = radius of the cylinder = $\frac{\text{Diameter}}{2}$ = $\frac{1.1 }{2}$ = 0.55 m

h = height of the cylinder = 1.4 m

$\pi$ = 3.142 (given)

So, the lateral surface area of a cylindrical water tank = $2 \times 3.142 \times 0.55 \times 1.4$

= 4.84 $\text{m}^{2}$ .

Now, it is given in the question that; Tublu uses 250 ml to cover 1 $\text{m}^{2}$ area, this means that;

To cover 4.84 $\text{m}^{2}$ area, he will use paint = $4.84 \times 250$ = 1210 ml

Since he has a full 2 liters tin of paint in his store which is equal to 2000 ml but he need only 1210 ml of paint.

This means that yes, he will have enough paint to cover the tank with one layer of paint.

8 0

3 years ago