Question

Find the equation of a line that is perpendicular to y=−12x−1 and passes through the point (3,2).

Answer 1

Answer:

y = (1/12)*x + 7/4

Step-by-step explanation:

y=−12x−1

Perpendicular line:

y = a*x + b

y = (1/12)*x + b

2 = (1/12) * 3 + b

2 = (3/12) + b

2 = 1/4 + b

2 - 1/4 = b

7/4 = b

Perpendicular line:

y = (1/12)*x + 7/4