Find the equation of a line that is perpendicular to y=−12x−1 and passes through the point (3,2).
1 answer:
Answer:
y = (1/12)*x + 7/4
Step-by-step explanation:
y=−12x−1
Perpendicular line:
y = a*x + b
y = (1/12)*x + b
2 = (1/12) * 3 + b
2 = (3/12) + b
2 = 1/4 + b
2 - 1/4 = b
7/4 = b
Perpendicular line:
y = (1/12)*x + 7/4
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