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qwelly [4]
4 years ago
11

Find the equation of a line that is perpendicular to y=−12x−1 and passes through the point (3,2).

Mathematics
1 answer:
Afina-wow [57]4 years ago
4 0

Answer:

y = (1/12)*x + 7/4

Step-by-step explanation:

y=−12x−1

Perpendicular line:

y = a*x + b

y = (1/12)*x + b

2 = (1/12) * 3 + b

2 = (3/12) + b

2 = 1/4 + b

2 - 1/4 = b

7/4 = b

Perpendicular line:

y = (1/12)*x + 7/4

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NEED HELP WITH HW!!!! (will mark brainliest)
Alex787 [66]
Let number of biscuits baked = x. (3/7)x are in container a. The remainder = (4/7)x, because (3/7)x + (4/7)x = (7/7)x = x. Now, (5/8)*(4/7)x = (5/14)x are in container b. The rest = (3/8)*(4/7)x, because (5/8)*(4/7)x + (3/8)*(4/7)x = (8/8)*(4/7)x = (4/7)x. So, (3/8)*(4/7)x = (3/14)x are in container c.
6 0
3 years ago
Three times the sum of half carlita's age and 3 is at least 12 .what values represent carlita's possible age? Graph the solution
Naya [18.7K]

Answer:

18 years

Step-by-step explanation:

let catrinas age be c

3(c/2)+3=12

3c/6=9

3c=54

c=18

6 0
3 years ago
Write the following in exponential form 10,000x10
EleoNora [17]

Answer:

1.0 x 10⁵

Step-by-step explanation:

10,000 • 10 = 100,000

= 1.0 x 10⁵

7 0
4 years ago
Given that a­­^b = x, evaluate the following:<br><br><br>2a^3b +a^2b +a^b
8090 [49]

Answer:

  2x^3 + x^2 + x

Step-by-step explanation:

For ...

a^{b}=x

The expression ...

2a^{3b}+a^{2b}+a^{b}

can be rewritten as ...

2(a^{b})^3+(a^b)^2+(a^b)=2x^3+x^2+x

5 0
3 years ago
Can I get some help?​
ruslelena [56]

Answer:

y = 4x - 9

Step-by-step explanation:

The points on the graph we can see clearly are (1, -5) and (2, -1).

The equation of the line is in the form <u>slope-intercept</u>, where the general formula is y = mx + b.

We need to find "m", the slope of the line; and "b", the y-intercept.

Use the two points we found in the formula for calculating slope m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}.

Choose which is point 1 and point 2:

Point 1 (1, -5)    x₁ = 1   y₁ = -5

Point 2 (2, -1)   x₂ = 2  y₂ = -1

Substitute x₁, x₂, y₁, and y₂

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{-1-(-5)}{2-1}       Solve in the numerator and denominator

m=\frac{4}{1}        Simplify the fraction

m=4           Slope of the line

Find "b":

Substitute a point's "x" and "y" coordinates, and the slope, "m", into the general formula for slope-intercept.

I will use point 2:

x = 2; y = -1; m = 4

y = mx + b

-1 = (4)(2) + b         Multiply

-1 = 8 + b            Start isolating "b"

-1 - 8 = 8 - 8 + b            Subtract 8 from both sides

-1 - 8 = b           "b" is isolated

b = -9           Answer for "b", y-intercept.

The variable should be on the left side for standard formatting.

Take the general formula: y = mx + b

Replace "m" and "b" with the values we found.

y = 4x - 9

8 0
3 years ago
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