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qwelly [4]
4 years ago
11

Find the equation of a line that is perpendicular to y=−12x−1 and passes through the point (3,2).

Mathematics
1 answer:
Afina-wow [57]4 years ago
4 0

Answer:

y = (1/12)*x + 7/4

Step-by-step explanation:

y=−12x−1

Perpendicular line:

y = a*x + b

y = (1/12)*x + b

2 = (1/12) * 3 + b

2 = (3/12) + b

2 = 1/4 + b

2 - 1/4 = b

7/4 = b

Perpendicular line:

y = (1/12)*x + 7/4

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3 years ago
the length of the shadow of a pole on level ground increases by 90m when the angle of elevation of the sun changes from 58 degre
Anarel [89]

Answer:

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Step-by-step explanation:

The given parameters are;

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We have a triangle formed by the change in the length of the shadow and the rays from the two angle of elevation to the top of the pole giving an angle 22° opposite to the increase  in the length of the shadow  

We have by sin rule;

90/(sin (22°)  = (Initial ray from the top of the pole to the end of the shadow's length)/(sin(122°)

Let the initial ray from the top of the pole to the end of the shadow's length = l₁

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3 years ago
Read 2 more answers
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