Answer:
B) 1.078 < 1.23 (T)
Step-by-step explanation:
A) 1.23 < 1.203 (F)
B) 1.078 < 1.23 (T)
C) 1.17 > 1.203 (F)
D) 1.078 > 1.17 (F)
Given:
The power generated by an electrical circuit (in watts) as a function of its current x (in amperes) is modeled by

To find:
The current which will produce the maximum power.
Solution:
We have,


Differentiate with respect to x.

...(i)
To find the extreme point equate P'(x)=0.


Divide both sides by -30.

Differentiate (i) with respect to x.

(Maximum)
It means, the given function is maximum at x=4.
Therefore, the current of 4 amperes will produce the maximum power.
Solve in this order:
Parenthesis
E
Multiplication
Division
Addition
Subtraction
Y=7x+1
*note that the first number is always the x.
so,
a) (0,?)
y=7(0)+1
y=1
(0,1)
b) (3,?)
y=7(3)+1
y=21+1
y=22
(3,22)
Answer:
-5
Step-by-step explanation:
Moving all terms of the quadratic to one side, we have
.
A quadratic has one real solution when the discriminant is equal to 0. In a quadratic
, the discriminant is
.
(The discriminant is more commonly known as
, but I changed the variable since we already have a
in the quadratic given.)
In the quadratic above, we have
,
, and
. Plugging this into the formula for the discriminant, we have
.
Using the distributive property to expand and simplifying, the expression becomes

Setting the discriminant equal to 0 gives
.
We can then solve the equation as usual: first, divide by 2 on both sides:
.
Squaring both sides gives
,
and subtracting 5 from both sides, we have
