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suter [353]
3 years ago
13

Find the measure of each angle on the circle graph using proportions

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
8 0
30 16 44 18 2 and 0 that's all ok hahahahahahaa
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A scientist listed the volumes, in milliliters, of some liquids used in an experiment.
Aloiza [94]

Answer:

B) 1.078 < 1.23  (T)

Step-by-step explanation:

A) 1.23 < 1.203  (F)

B) 1.078 < 1.23  (T)

C) 1.17 > 1.203  (F)

D) 1.078 > 1.17 (F)

4 0
3 years ago
Read 2 more answers
The power generated by an electrical circuit (in watts) as a function of its current x xx (in amperes) is modeled by P ( x ) = −
marysya [2.9K]

Given:

The power generated by an electrical circuit (in watts) as a function of its current x (in amperes) is modeled by

P(x)=-15x(x-8)

To find:

The current which will produce the maximum power.

Solution:

We have,

P(x)=-15x(x-8)

P(x)=-15x^2+120x

Differentiate with respect to x.

P'(x)=-15(2x)+120(1)

P'(x)=-30x+120      ...(i)

To find the extreme point equate P'(x)=0.

-30x+120=0

-30x=-120

Divide both sides by -30.

x=4

Differentiate (i) with respect to x.

P'(x)=-30(1)+(0)

P'(x)=-30 (Maximum)

It means, the given function is maximum at x=4.

Therefore, the current of 4 amperes will produce the maximum power.

7 0
3 years ago
Help help please i need help
antoniya [11.8K]
Solve in this order:

Parenthesis
E
Multiplication
Division
Addition
Subtraction
7 0
2 years ago
Find the missing coordinate to complete the​ ordered-pair solution to the given linear equation.
ad-work [718]
Y=7x+1

*note that the first number is always the x. 
so, 

a) (0,?)
    y=7(0)+1
    y=1
    (0,1)

b) (3,?)
    y=7(3)+1
    y=21+1
    y=22
    (3,22)
6 0
3 years ago
Read 2 more answers
For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

\sqrt{c+5}=0.

Squaring both sides gives

c+5=0,

and subtracting 5 from both sides, we have

\boxed{c=-5}.

3 0
2 years ago
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