4500 + 1.20x < 4.80x
4500 < 4.80x - 1.20x
4500 < 3.60x
4500/3.60 < x
1250 < x.......minimum number would be 1251
Since, population of species A is represented by : 
Let us find the population of species A, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e., 
Also, since population of species B is represented by : 
Let us find the population of species B, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e.,
Thus, at the end of 1 week, species A and species B will have the same population.
Hence, option D is correct.
Answer:
This is the graph of y = 0.4x
Answer:
Step-by-step explanation:
Since the inscribed angle theorem tells us that any inscribed angle will be exactly half the measure of the central angle that subtends its arc, it follows that all inscribed angles sharing that arc will be half the measure of the same central angle. Therefore, the inscribed angles must all be congruent.
Answer (2x + 7) • (x2 - 2)
Step-by-step explanation:
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Step by step solution :
Step 1 :
Trying to factor as a Difference of Squares :
1.1 Factoring: x2-2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 2 is not a square !!
Ruling : Binomial can not be factored as the difference of two perfect squares.
Final result :
(2x + 7) • (x2 - 2)
