Similar polygons are polygons whose corresponding angles are congruent and their corresponding sides are proportional. In other words, Polygons that have the same shape but not necessarily the same size are called similar polygons.
Now, we can write the equation of that relates length and width:
(Equation #1)
The area of the yard can be expressed as (using equation #1 into #2):
(Equation #2)
Since the Area of the yard is , then equation #2 turns into:
Now, we rearrange this equation:
We can divide the equation by 5 :
We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since and . The equation factorised looks like this:
Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:
Therefore, the dimensions of the yard are W=20ft and L=40ft.
Part A: This data does represent a function because no value of x is repeated. Part B: If x = 6 for the relation f(x) = 7x - 15, then f(x) will equal 27. The function f(x) = 7x - 15 will have the greater value Part C: If f(x) is equal to 6 then x will equal 3