Given that the point (-2,8) is on the graph of an equation that is symmetric with respect to the x-axis, what other point is on
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Answer:
slope of 2y- 5X = -20: m=
Convert to standard form: 5x- 2y=20
Slope using standard form: m=5/2
slope - Intercept form of 2y-5x= -20:
y=mx+b
y=5/2x-10
Axis interception points of 5/2x-10:
X Intercepts: (4, 0),
Y Intercepts: (0, - 10)
