Given that the point (-2,8) is on the graph of an equation that is symmetric with respect to the x-axis, what other point is on
1 answer:
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the absolute value of the product of the zeros of a is .
<u>Step-by-step explanation:</u>
Here we have , is a polynomial function of t, where k is a constant. Given that a(2) = 0 . We need to find the absolute value of the product of the zeros of a . Let's find out:
Equation every factor of a(t) to zero we get:
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⇒
⇒
But , t=2 So , . Now , the absolute value of the product of the zeros of a is :
⇒
⇒
⇒
Therefore, the absolute value of the product of the zeros of a is .
See the picture attached to better understand the problem
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer is
jn=16
we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm
we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12
jn=jl*jk/jm-----> jn=12*8/6----> jn=16
the answer is
jn=16