Answer:
1. 51
2.25
3.104
4.31
5.41
Step-by-step explanation:
Answer:
0.138repeating
Step-by-step explanation:
Answer:
y=7(x-5)+3
Step-by-step explanation:
Answer:
Jenny save 4 times
for the month
Step-by-step explanation:
Given Jenny has saved
over the last 12 months.
She saved either
or
a month.
Let the number of months to save
be x
Let the number of months to save
be y
Total period is 12 month.

Jenny has saved $3,800 over the last 12 months.

Dividing both side from 50 we get,


Now Multiplying equation 1 by 5 we get,

Now Subtracting Equation 3 by equation 2 we get,

Substituting the value of y in equation 1 we get,

∴ Jenny save 4 Months of
and 8 Months of
in a 12 month duration
The number of solutions of a quadratic equation
ax^2+bx+c=0
Depends on its discriminant
/Delta=b^2-4ac
If /Delta>0 there are two distinct solutions
If /Delta=0 there are two coincident solutions
If /Delta<0 there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
The number of solutions of a quadratic equation
Depends on its discriminant
If there are two distinct solutions
If there are two coincident solutions
If there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
b^2-4ac=9+28t>0\iff t>-\dfrac[9][28]