We are given with two equations 2x − 3y = −1 and <span>11x − 9y = −13. The problem says that when the first equation is multiplied by -3 which results to -6x + 9y = 3, the sum of the resulting equation and the second one is equal to 5x = -10. We verify this: -6x + 11x = 5x while -9 y and 9 y cancels out. 3+-13 equals -10. Hence the total is really 5x = - 10.</span>
Y=3(x+1)(x-5)
I'm going to ignore 3 for now, but will add it later.
FOIL the (x+1)(x-5)
F = multiply the First numbers x and x
O = multiply the Outside numbers x and -5
I = multiply the Inside number 1 and x
L = multiply the Last numbers 1 and -5
3(x^2 + -5x + 1x + -5)
add -5x and x
3(x^2 + -4x + -5)
multiply the numbers inside the parenthesis by 3
3x^2 + -12x + -15
76÷2 = 38. 38 es la solución.
Answer:
YZ=16
Step-by-step explanation:
Because they are parallel