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Angelina_Jolie [31]
3 years ago
15

The Biot-Savart force law predicts the force on a charge moving ____ to a magnetic field.

Physics
1 answer:
Pavel [41]3 years ago
8 0
I think it’s parallel
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Biologists think that some spiders "tune" strands of their web to give enhanced response at frequencies corresponding to those a
Nat2105 [25]

Answer:

Explanation:

Given

diameter d=20 \mu m

density \rho =1300 kg/m^3

frequency \nu =150 Hz

Length of silk strand L=14 cm

Velocity in the string is as follows

\nu =\sqrt{\frac{T}{\mu }}

The expression for Fundamental Frequency

f=\frac{\nu }{2l}

f=\frac{1}{2l}\times \sqrt{\frac{T}{\mu }}

f=\frac{1}{2l}\times \sqrt{\frac{T}{\frac{m}{l}}}

f=\frac{1}{2l}\times \sqrt{\frac{Tl}{\rho V}}

Squaring

f^2=\frac{1}{4l^2}\times \frac{Tl}{\rho V}

T=4\rho \cdot A\cdot l^2\cdot f^2

T=4\times 1300\times \frac{\pi }{4}(20\times 10^{-6})^2\times (0.14)^2\times 150^2

T=7.2\times 10^{-4} N

8 0
4 years ago
If red light hits a red filter, what kind of light comes through the filter?
Roman55 [17]
A. red, is the correct answer. A red filter only lets red light through, whether white or red light passes through it.
Hope this helps, and have a great day!

8 0
4 years ago
Waves with higher amplitude transfer ____energy.
natali 33 [55]

Answer:

- Waves with higher amplitude transfer HIGHER energy.

- Waves with higher frequency transfer HIGHER energy.

3 0
3 years ago
Help I need an answer!
Umnica [9.8K]

You apparently haven't noticed yet . . .

The moon rises in the East, moves across the sky, and sets
in the West, just like the sun and everything else in the sky.

It takes the moon about 12 hours and 25 minutes to go from
rising to setting, and then it rises again about 24 hours and
49 minutes later.  So each day, the moon rises about 49 minutes
later than it rose on the previous day.

In order to describe the direction and height of the moon in the sky,
you need to tell the date and the time, and also the latitude on Earth
from which you observed it.  And wherever the moon was in the sky
at that time, it was in a noticeably different place 30 minutes later.

Just like the sun.

5 0
3 years ago
An object of mass m travels along the parabola yequalsx squared with a constant speed of 5 ​units/sec. What is the force on the
Dmitriy789 [7]

Explanation:

The object is moving along the parabola y = x² and is at the point (√2, 2).  Because the object is changing directions, it has a centripetal acceleration towards the center of the circle of curvature.

First, we need to find the radius of curvature.  This is given by the equation:

R = [1 + (y')²]^(³/₂) / |y"|

y' = 2x and y" = 2:

R = [1 + (2x)²]^(³/₂) / |2|

R = (1 + 4x²)^(³/₂) / 2

At x = √2:

R = (1 + 4(√2)²)^(³/₂) / 2

R = (9)^(³/₂) / 2

R = 27 / 2

R = 13.5

So the centripetal force is:

F = m v² / r

F = m (5)² / 13.5

F = 1.85 m

7 0
3 years ago
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