Answer:
From lowest to highest acceleration:
3rd train
2nd train
1st train
Explanation:
The acceleration of an object can be found by using Newton's second law:
where
a is the acceleration
F is the net force on the object
m is the mass of the object
We notice that for equal values of the forces F, the acceleration a is inversely proportional to the mass, m. Therefore, greater mass means lower acceleration, and viceversa.
So, the train with lowest acceleration is the one with largest mass, i.e. the 3rd train consisting of 50 equally loaded freight cars. Then, the 2nd train has larger acceleration, since it consists of 50 empty freight cars (so its mass is smaller). Finally, the 1st train (a single empty car) is the one with largest acceleration, since it is the train with smallest mass.
It's a homogeneous mixture
<span />
Answer:
Explanation:
Given:
- minimum amplitude at the start of oscillation cycle,
- the first maximum amplitude after the start of oscillation cycle,
- Time taken to reach from the first minima to the first maxima,
As we know that an oscilloscope executes a wave cycle represented by a sine wave. So we can deduce that it has executed one-fourth of the cycle in going from the amplitude of 20 units to 100 units in 0.005 seconds.
<u>So the time taken to complete one cycle of the oscillation:</u>
is the time period of the oscillation
<u>We know frequency:</u>
Density= population/area
area= 12 X 7 = 84 m^2
density= 168/84= 2 mice per m^2
Answer:
(a) warm air is forced upward where it cools;
(c) cumulonimbus or nimbo-stratus clouds form
(d) thunderstorms with heavy showers and gusty winds occur"
(b) air cools and sinks, pressure rises, rain stops;
Explanation:
- A cold for front is a denser air , as that forms under the warmer and lighter air mass and this causes a low pressure along the cold form and thus causes the formation of a thunderstorm where enough moisture is present and drop in temperature occurs and in the northern hemisphere the cold front shifts the winds to from the southwest to northwest clockwise.
