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2 years ago

Which choice is NOT a way to find 7 ÷ 3? A- 1/3 of 7 B- 7 × 1/3 C- 1/7 of 3 D- 7/3

Mathematics

2 answers:

Igoryamba2 years ago

6 0

C is wrong. A B C and 7 divided by 3 equal 2.33. C equals 0.43

lutik1710 [3]2 years ago

4 0

The answer is C) 1/7 of 3.
Because all others are correct and this one is incorrect.

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I would appreciate the help, please!!!

kvv77 [185]

Answer:

ASA

Step-by-step explanation:

Angle Side Angle congruent

∠2 = ∠3 ; AC ; ∠1 = ∠4

6 0

2 years ago

Jerome tries to find the value of the expression 3 - 6 + 5 by first applying the commutative property.He rewrites the expression

Afina-wow [57]

By moving the signs he actually changed the number itself. He changed -6 from a negative to a positive and 5 from a positive to a negative. Both equations give different answers.

Hopefully this helps :)

8 0

2 years ago

I need help pleaseeee

algol13

Answer:

Option A

Step-by-step explanation:

Thisbis because when two of them are hanged on the same side it means that it's addition. (Addition of weight)

8 0

2 years ago

Read 2 more answers

You order 10 large aspen trees from a nursery. They will deliver them to you at a cost of $25 for the first tree plus $5 for eve

natka813 [3]

Answer:

D. $70

Step-by-step explanation:

you can first think that the first tree is $25 plus the nine trees for 5 dollars so

5x9=45

45+25=70

Hope this helps :D

3 0

2 years ago

Find the length of the curve y = integral from 1 to x of sqrt(t^3-1)

Arlecino [84]

$y=\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt$

By the fundamental theorem of calculus,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm d}{\mathrm dx}\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt=\sqrt{x^3-1}$

Now the arc length over an arbitrary interval $(a,b)$ is

$\displaystyle\int_a^b\sqrt{1+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx=\int_a^b\sqrt{1+x^3-1}\,\mathrm dx=\int_a^bx^{3/2}\,\mathrm dx$

But before we compute the integral, first we need to make sure the integrand exists over it. $x^{3/2}$ is undefined if $x$ , so we assume $a\ge0$ and for convenience that $a$ . Then

$\displaystyle\int_a^bx^{3/2}\,\mathrm dx=\frac25x^{5/2}\bigg|_{x=a}^{x=b}=\frac25\left(b^{5/2}-a^{5/2}\right)$

6 0

2 years ago