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Bumek [7]
2 years ago
12

If each of the 4 shelves holds 12 movies, how many movies does Betty have on her shelving unit? Show your work.

Mathematics
2 answers:
Ivanshal [37]2 years ago
8 0

Answer:

48 Movies

Step-by-step explanation:

If each of the 4 shelves hold 12 movies you'd multiply 12*4.

Anna [14]2 years ago
3 0

Answer:

48

Step-by-step explanation:

Simply multiply 4 by 12

equals 48

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5600 to the nearest 1000​
dem82 [27]

Answer:

6000.

Step-by-step explanation:

Hundreds digit is 6 so we round up the thousand digit (5) to get 6000.

5 0
2 years ago
A number a decreased by 7 is 2.
umka21 [38]

Answer:

9

Step-by-step explanation:

Let's first convert this to numbers. When a number is decreased by a certain amount, that is the same as saying that something is subtracted from it. Therefore:

a-7=2

Add 7 to both sides:

a-7+7=2+7

a=9

Hope this helps!

7 0
3 years ago
Read 2 more answers
Dont know how to solve for x can someone help me
vfiekz [6]
  57 + x + x + 130 = 167
  57 + 2x + 130 = 167
    187 + 2x = 167
  - 187          - 187
---------------------------
    2x = -20
  ------  -------
     2       2

x = -10
5 0
3 years ago
Both students made a mistake.
Musya8 [376]
I’m so sorry! I hope you find the answer soon! I’m stressing out as well
5 0
2 years ago
Suppose that the amount of time T a customer spends in a bank is exponentially distributed with an average of 10 minutes. What i
Bad White [126]

Answer:

The probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is 0.6065.

Step-by-step explanation:

The random variable <em>T</em> is defined as the amount of time a customer spends in a bank.

The random variable <em>T</em> is exponentially distributed.

The probability density function of a an exponential random variable is:

f(x)=\lambda e^{-\lambda x};\ x>0

The average time a customer spends in a bank is <em>β</em> = 10 minutes.

Then the parameter of the distribution is:

\lambda=\frac{1}{\beta}=\frac{1}{10}=0.10

An exponential distribution has a memory-less property, i.e the future probabilities are not affected by any past data.

That is, <em>P</em> (<em>X</em> > <em>s</em> + <em>x</em> | <em>X</em> ><em> s</em>) = <em>P</em> (<em>X</em> > <em>x</em>)

So the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is:

P (X > 15 | X > 10) = P (X > 5)

\int\limits^{\infty}_{5} {f(x)} \, dx =\int\limits^{\infty}_{5}  {\lambda e^{-\lambda x}} \, dx\\=\int\limits^{\infty}_{5}  {0.10 e^{-0.10 x}} \, dx\\=0.10\int\limits^{\infty}_{5}  {e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10}|^{\infty}_{5}\\=[-e^{-0.10 \times \infty}+e^{-0.10 \times 5}]\\=0.6065

Thus, the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is 0.6065.

8 0
3 years ago
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