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katrin [286]
3 years ago
7

What would the angle be! asap answer

Mathematics
2 answers:
brilliants [131]3 years ago
6 0

Answer:

111°

Step-by-step explanation:

the sum of the outer angles of a triangle is alway 180

so 180-82-29= 69°

180-69= 111°

LekaFEV [45]3 years ago
5 0

Answer:

x = 111°

Step-by-step explanation:

Angles in a triangle add up to 180

180 - (29+82) = 69

Angles on a straight line add up to 180

180 - 69 = 111

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What is the rate of change and initial value for the linear relation that includes the points shown in the table?
melomori [17]

Answer: I need the table to give the answer

Step-by-step explanation: copy and paste the table

5 0
3 years ago
Geometry help!!
Eduardwww [97]
It would be A, Side Angle Side (SAS).  Because you are given we congruent sides, and tow right angles.  Using the reasoning of "If two two angles are both right angles then they are congruent" you can prove the angles congruent. 

The reason it is not HL is because HL is used when it is given a right angle and the hypotenuse and one of the legs congruent.  Therefore the only choice is Side Angle Side (SAS).
3 0
3 years ago
When knowing x how do you find y?
ludmilkaskok [199]
You need to divide y by x to get your answer
5 0
3 years ago
Given the function f(x)=4x-9, evaluate and simplify the following f(-6) and f(4)
saveliy_v [14]

Answer:

<h2>f(-6) = -33, f(4) = 7</h2>

Step-by-step explanation:

f(x)=4x-9

f(-6), f(4)

Put x = -6 and x = 4 to the equation of the function:

f(-6)=4(-6)-9=-24-9=-33\\\\f(4)=4(4)-9=16-9=7

4 0
3 years ago
What is the nth term rule of the quadratic sequence below? 4,15,30,49,72,99,130,...
navik [9.2K]

Answer:

The nth term rule of the quadratic sequence is 2n^{2} +5n-3.

Step-by-step explanation:

We are given the following quadratic sequence below;

4, 15, 30, 49, 72, 99, 130,...

As we know that the formula for the nth term of the quadratic sequence is given by =  an^{2}+bn+c

Firstly, we will find the difference between the term of the given sequence;

1st difference of the given sequence;

(2nd term - 1st term), (3rd term - 2nd term), (4th term - 3rd term), (5th term - 4th term), (6th term - 5th term), (7th term - 6th term)

= (15 - 4), (30 - 15), (49 - 30), (72 - 49), (99 - 72), (130 - 99),....

= (11, 15, 19, 23, 27, 31,.....)

Now, we will find the second difference of the given sequence, i.e;

= (15 - 11), (19 - 15), (23 - 19), (27 - 23), (31 - 27),....

= (4, 4, 4, 4, 4)

Since the differences are same now, so to find the value of a we have to divide the value of second difference by 2, i.e;

The value of a  =  \dfrac{4}{2} = 2

SO, the first term of the nth term rule equation is an^{2} = 2n^{2}.

Now, in the term 2n^{2}, put the value of n = 1, 2, 3, 4 and 5 and then form the sequence, i.e;

If n = 1, then 2n^{2} = 2 \times (1)^{2} = 2

If n = 2, then 2n^{2} = 2 \times (2)^{2} = 8

If n = 3, then 2n^{2} = 2 \times (3)^{2} = 18

If n = 4, then 2n^{2} = 2 \times (4)^{2} = 32

If n = 5, then 2n^{2} = 2 \times (5)^{2} = 50

SO, the sequence formed is (2, 8, 18, 32, 50).

Now, find the difference of this sequence and the original quadratic sequence, i.e;

= (4 - 2), (15 - 8), (30 - 18), (49 - 32), (72 - 50)

= (2, 7, 12, 17, 22)

Now, as we can see that the above sequence resembles the general form of (5n - 3) because:

If we put n = 1, then (5n - 3) = 5 - 3 = 2

If we put n = 2, then (5n - 3) = 10 - 3 = 7 and so on....

From this, we concluded that the value of b and c are 5 and (-3) respectively.

Hence, the nth term rule for the given quadratic sequence is 2n^{2} +5n-3.

7 0
3 years ago
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