Answer:
The amount of acid in third container is =42%
Step-by-step explanation:
Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .
Let, the volume of first container is = x
Then , the volume of second container = (x+ x of 50%)
= x + 0.5 x
= 1.5 x
Therefore the amount of acid in first container 
= 0.3 x
The amount of acid in second container 
= 0.75x
Total amount of acid= 0.3x + 0.75x = 1.05 x
Total amount of solution = x+1.5x = 2.5x
The amount of acid in third container is = 
%
= 42%
Answer: The total change is 21.
Since you want to find the change from the lowest to highest, make it into a subtraction problem. First of all, take the smallest number in front of the largest.
20 -1
Next, add a minus sign in between, your equation should look like this:
20 - (-1) = x
Then, you cancel out the negative signs. After that you solve it
20 - (-1) -> 20 + 1.
Lastly, you add them together.
20 + 1 = 21.
In conclusion, the answer is 21.
Slope
m = (y2-y1)/(x2-x1)
m = (10 - 7)/(2 --1)
m = 3/3
m = 1
To find the equation
y = mx + b
m is slope
y = 1x + b
plug in one of the equations to solve for b
10 = 1(2) + b
10 = 2 + b
subtract 2 from both sides
8 = b
The equation is
y = 1x + 8
or you can write it as
y = x + 8
Hope this helps
