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sesenic [268]
3 years ago
7

Diana uses 30 grams of coffee beans to make 48 fluid ounces of coffee. When the company comes she makes 100 fluid ounces of coff

ee. How many grams of coffee beans does Diana use when the company comes
Mathematics
2 answers:
murzikaleks [220]3 years ago
7 0
Sixty four fluid ounces hope that helped

AfilCa [17]3 years ago
6 0
<h2>Answer:</h2>

The grams of coffee beans Diana uses when the company comes is:

                              62.5 grams

<h2>Step-by-step explanation:</h2>

It is given that:

  48 fluid ounces of coffee requires :   30 grams of coffee.

This means that 1 fluid ounces of coffee requires: 30/48 grams of coffee.

Hence,

100 fluid ounces of coffee requires:

(30/48)×100 grams of coffee

=62.5 grams of coffee.

      Hence, the answer is:

          62.5 grams

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Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
3 years ago
Need help ASAP with the correct answer
Ymorist [56]
F = 2t - 3
f = 2(7) - 3
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12.6 + 4m = 9.6 + 8m
Sergeu [11.5K]

Answer:

3 = 4m or  0.75 = m

Step-by-step explanation:

12.6 + 4m = 9.6 + 8m

Subtract 4m from both sides of the equation

12.6 = 9.6 + 4m

Subtract 9.6 from both sides of the equation

3 = 4m

Divide by four on both sides of the equation

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3 years ago
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You multiply the number by itself however many times it says for example 2 to the second power 2x2 is 4
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