Answer:
see below
Step-by-step explanation:
First we need to draw segment UT
We are using similar triangle
Triangle BTU is similar to triangle EUT
UT ≅ TU reflexive property
BT ≅ EU given
BU ≅ ET given
△UBT ≅ △TEU by SSS congruence postulate
<B ≅ <E corresponding parts of congruent triangles are congruent
The answer is going to be 5
Answer: Cost of DVD is $2.95 and cost of games is $3.2.
Step-by-step explanation:
Let the cost of DVD be x
Let the cost of games be y
So, According to question,
![2x+3y=\$15.50\\\\and\\\\3x+1y=\$12.05](https://tex.z-dn.net/?f=2x%2B3y%3D%5C%2415.50%5C%5C%5C%5Cand%5C%5C%5C%5C3x%2B1y%3D%5C%2412.05)
Now, we will apply " Substitution Method " i.e.,
![2x=15.50-3y\\\\x=\frac{15.5-3y}{2}](https://tex.z-dn.net/?f=2x%3D15.50-3y%5C%5C%5C%5Cx%3D%5Cfrac%7B15.5-3y%7D%7B2%7D)
Put this value of x in second equation:
![3x+y=12.05\\\\3\times \frac{15.5-3y}{2}+y=12.05\\\\46.5-9y+2y=12.05\times 2\\\\46.5-7y=24.1\\\\46.5-24.1=7y\\\\22.4=7y\\\\\frac{22.4}{7}=y\\\\3.2=y](https://tex.z-dn.net/?f=3x%2By%3D12.05%5C%5C%5C%5C3%5Ctimes%20%5Cfrac%7B15.5-3y%7D%7B2%7D%2By%3D12.05%5C%5C%5C%5C46.5-9y%2B2y%3D12.05%5Ctimes%202%5C%5C%5C%5C46.5-7y%3D24.1%5C%5C%5C%5C46.5-24.1%3D7y%5C%5C%5C%5C22.4%3D7y%5C%5C%5C%5C%5Cfrac%7B22.4%7D%7B7%7D%3Dy%5C%5C%5C%5C3.2%3Dy)
Now, substitute the value of y in equation of x:
![x=\frac{15.5-3y}{2}\\\\x=\frac{15.5-3\times3.2}{2}\\\\x=\frac{15.5-9.6}{2}\\\\x=\frac{5.9}{2}\\\\x=2.95](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B15.5-3y%7D%7B2%7D%5C%5C%5C%5Cx%3D%5Cfrac%7B15.5-3%5Ctimes3.2%7D%7B2%7D%5C%5C%5C%5Cx%3D%5Cfrac%7B15.5-9.6%7D%7B2%7D%5C%5C%5C%5Cx%3D%5Cfrac%7B5.9%7D%7B2%7D%5C%5C%5C%5Cx%3D2.95)
Hence, Cost of DVD is $2.95 and cost of games is $3.2.
Answer:
yes
Step-by-step explanation:
They both are 0.6 in decimal form
We will use binomial
distribution in this problem.
<span>The solution would be like
this for this specific problem:
</span><span>P(default) = p = 4% = 0.04 </span><span>
<span>q = 1-p = 1-0.04 = 0.96 </span>
n = 5</span>
<span>P(r) = nCr*q^(n-r)*p^r </span>
<span>Required probability =
P(r=2) = 5C2*0.96^3*0.04^2 </span>
= 0.0142 OR 1.42%
<span>The probability that at most
two customers in the sample will default on their payments is 1.42%.</span>