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3 years ago

An object accelerates 2.0 m/s2 when a force of 12.0 newtons is applied to it. What is the mass of the object?

Physics

1 answer:

julia-pushkina [17]3 years ago

4 0

Answer: 6kg

Explanation:

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(a) When a battery is connected to the plates of a 8.00-µF capacitor, it stores a charge of 48.0 µC. What is the voltage of the

frosja888 [35]

Answer:

a.6 V

b.24 V

Explanation:

We are given that

a. $C=8\mu F=8\times 10^{-6} F$

$1\mu =10^{-6}$

Q= $48\mu C=48\times 10^{-6} C$

We know that

$V=\frac{Q}{C}$

Using the formula

$V=\frac{48\times 10^{-6}}{8\times 10^{-6}}=6 V$

b. $Q=192\mu C=192\times 10^{-6} C$

$V=\frac{192\times 10^{-6}}{8\times 10^{-6}}=24 V$

8 0

3 years ago

Galaxies are separated by?

Inessa [10]

It is number c I think

8 0

3 years ago

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A solid 200-g block of lead and a solid 200-g block of copper are completely submerged in an aquarium filled with water. Each bl

finlep [7]

Answer:

B. The buoyant force on the copper block is greater than the buoyant force on the lead block.

Explanation:

Given;

mass of lead block, m₁ = 200 g = 0.2 kg

mass of copper block, m₂ = 200 g = 0.2 kg

density of water, ρ = 1 g/cm³

density of lead block, ρ₁ = 11.34 g/cm³

density of copper block, ρ₂ = 8.96 g/cm³

The buoyant force on each block is calculated as;

$F_B = mg(\frac{density \ of \ fluid}{density \ of \ object} )$

The buoyant force of lead block;

$F_{lead} = 0.2*9.8(\frac{1}{11.34} )\\\\F_{lead} = 0.173 \ N$

The buoyant force of copper block

$F_{copper} = 0.2*9.8(\frac{1}{8.96})\\\\F_{copper} = 0.219 \ N$

Therefore, the buoyant force on the copper block is greater than the buoyant force on the lead block

3 0

3 years ago

Which phase of matter makes up stars?

nydimaria [60]

I believe it’s gas because that’s all that stars are really made of

4 0

3 years ago

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By what angle should the second polarized sheet be rotated relative to the first to reduce the transmitted intensity to one-half

algol [13]

Answer:

θ = 45º

Explanation:

The light that falls on the second polarized is polarized, therefore it is governed by the law of Maluz

I = I₀ cos² θ

in the problem they ask us

I = ½ I₀

let's look for the angles

½ I₀ = I₀ cos² θ

cos θ = √ ½ = 0.707

θ = cos 0.707

θ = 45º

6 0

3 years ago