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PSYCHO15rus [73]

4 years ago

10

What is the resistance of a resistor if the potential difference across the resistor is 20.0 V when a current of 10.0 A flows th

rough the resistor?

1 answer:

notka56 [123]4 years ago

8 0

Answer:

The answer of your question is 2, I think so

Explanation:

R = V/I

R = 20/10=2

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Instead of clear-cutting land and moving on, a local lumber business decides to start farming trees: cutting some of the trees a

Nuetrik [128]

I think your answer would be C. because they are replacing the trees they are cutting down.

5 0

3 years ago

Read 2 more answers

Which of the following is an example of heat transfer by convection?

erastovalidia [21]

Answer: A. water within a pan is heated and flows in a circular path.

Explanation: Convection is a type of heat transfer that occurs in liquids and gases. Convection occurs when there is a contrast in temperature between two parts of a liquid or gas. The hot part of a fluid rises above, and the cooler part sinks to the bottom resulting to circular motion of the fluid.

6 0

4 years ago

An undamped 2.47 kg2.47 kg horizontal spring oscillator has a spring constant of 32.8 N/m.32.8 N/m. While oscillating, it is fou

olganol [36]

Answer:

0.631 m

6.53315 J

Explanation:

m = Mass = 2.47 kg

v = Velocity = 2.30 m/s

k = Spring constant = 32.8 N/m

A = Amplitude

In this system the energy is conserved

$\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{2.47\times 2.3^2}{32.8}}\\\Rightarrow A=0.631\ m$

The amplitude is 0.631 m

Mechanical energy is given by

$E=\dfrac{1}{2}mv^2\\\Rightarrow E=\dfrac{1}{2}2.47\times 2.3^2\\\Rightarrow E=6.53315\ J$

The mechanical energy is 6.53315 J

5 0

3 years ago

If a 42kg rolling object slows from 11.5m/s to 3.33m/s how much work did friction do

geniusboy [140]

Answer: 1608.39 J

Explanation: Given that the

mass M = 42kg

U = 11.5m/s

V = 3.33m/s

how much work did friction do

Work done = Force × distance

Work done = Ma × distance

But acceleration a = V/t

Work done = M × V/t × d

Work done = M × V × d/t

Where d/t = velocity

Therefore,

Work done = M × U × V

Work done = 42 × 11.5 × 3.33

Work done = 1608.39 J

8 0

3 years ago

If the graph shown is a position-time graph of an object moving at constant velocity, what is the velocity of the object? Assume

belka [17]

Answer:

C.) v = 50 m/s

Explanation:

The relationship between position vs. time graph and velocity is that the derivative (slope) of the position vs. time graph gives you velocity. In other words, find the slope to get the velocity.

Select two arbitrary points. I'll choose (3s, 225m) and (0s, 75m).

Now use the slope equation:

$v = \frac{y_{2} - y_{1} }{x_{2} - x_{1}} =\frac{225 - 75}{3-0} = 50 m/s$

v = 50 m/s

Hopes this helps!

5 0

3 years ago