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e-lub [12.9K]
2 years ago
5

rulfus has a box that contains cards of the same shape and size.there are 5 yellow cards, 4red cards, and 1 purple card.he draws

a card at random replaced it, and draws a second card .what is the probability that both cards will be red?
Mathematics
1 answer:
attashe74 [19]2 years ago
7 0

Answer:

P(Red\ and\ Red) = \frac{4}{25}

Step-by-step explanation:

Given

Yellow = 5

Red = 4

Purple = 1

Total = 10

Required

Determine the probability of selecting red, twice

Since it is a probability with replacement, the probability can be represented as:

P(Red\ and\ Red) = P(Red) * P(Red)

And this is calculated as follows:

P(Red\ and\ Red) = \frac{n(Red)}{Total} * \frac{n(Red)}{Total}

P(Red\ and\ Red) = \frac{4}{10} * \frac{4}{10}

P(Red\ and\ Red) = \frac{2}{5} * \frac{2}{5}

P(Red\ and\ Red) = \frac{4}{25}

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Answer:

Step-by-step explanation:

Hello!

The experiment was designed to proof if the physiological blind spot can be reduced with eye training.

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In this type of situation, where only one sample is taken and both variables are measured to the same observational unit (there is a pair of observations for each person), the observations are dependant and the corresponding test is the paired samples t-test.

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I hope it helps!

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3 years ago
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