The average annual rainfall will be more than 40.6 inches in about 2.1 percent of the years.
<h3>What is the
average annual rainfall?</h3>
Generally, the equation for the probability is mathematically given as
Therefore
The z score for the probability of 0.979 is 2.034, according to the table of z values.
In the given equation, replace the values of mu and sigma with their respective values, and then solve for x.
In conclusion, The average annual rainfall will be more than 40.6 inches in about 2.1 percent of the years.
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I'm hoping it might be around the .65 percentile?
Answer:
y = 
Step-by-step explanation:
As given , y' = 3y - 2y²
⇒y' - 3y = -2y²
Divide by y² in the above equation
⇒
⇒
........(1)
Now , let 
= u
⇒-
⇒-
∴ equation (1) becomes
-
- 3u = -2
⇒ + 3u = 2
It is a linear differential equation
Now,
Integrating factor = I.F = 
= 
∴ The solution becomes
u.(I.F) = 
+ C
⇒u.() = 
+ C
⇒u.() = 
+ C
⇒u = 
As = u
⇒ =
⇒ y = 
⇒ y =
Answer:
15. 50 kg
16a. 5 kg
16b. 3.75 kg
Step-by-step explanation:
The formula relating force, mass, and acceleration can be solved for mass. This formula will apply to both problems. We'll use m for both "mass" and "meters". We presume you can avoid getting mixed up by understanding that meters is used in the context of acceleration: m/s².
F = ma
m = F/a . . . . . divide by a
__
15. m = (250 N)/(5 m/s²) = 50 kg
__
16a. m = (15 N)/(3 m/s²) = 5 kg
16b. m = (15 N)/(4 m/s²) = 3.75 kg
_____
<em>Comment on units</em>
Especially for physics problems, I like to keep the units with the numbers. It is helpful to remember that Newtons are equivalent to kg·m/s². So, dividing Newtons by acceleration in m/s² will give mass in kg. Since you're familiar with F=ma, it's not too hard to remember that the units of force (N) are the product of the units of mass (kg) and acceleration (m/s²).
