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finlep [7]
3 years ago
15

A lending library has a fixed charge for the first three days and an additional charge for each day thereafter. Saritha paid ₹27

for a book kept for seven days, while Susy paid ₹21 for the book she kept for five days. Find the fixed charge and the charge for each extra day.​​
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
5 0

Answer:

Ji Gud afternoon.

I'm fine

what about you madam.

Hope u r fine and stay safe and healthy

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nasty-shy [4]

The vertical numbers are the distance and the horizontal numbers are the time in seconds.

Look at where the line is located at the number 20.

It si between the 2 and the 3 on the horizontal line, but you can see it is closer to the 2 than it is the 3, so the time would be 2.2s

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Helene drove 70 km on 4 L of gasoline. Which proportion would help determine how far she can travel on a full 30 L tank of gasol
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4 years ago
The two lines graphed below are parallel. How many solutions are there to the
dimulka [17.4K]

Answer:

<h2>Zero</h2>

Step-by-step explanation:

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3 years ago
The bad debt ratio for a financial institution is defined to the dollar value of loans defaulted divided by the total dollar val
vlabodo [156]

Answer:

Step-by-step explanation:

From the information given:

Consider X to be the random variable denoting the bad debt ratios for Ohio Bank.

Then, X \sim N ( \mu, \sigma ^2)

Thus the null hypothesis and the alternative can be computed as:

Null hypothesis:

H_o :  \mu \leq3.5\%

Alternative hypothesis

H_1 : \mu > 3.5\%

The type I and type II error is as follows:

Type I:

The mean bad debt ratio is > 3.5% when it is not

Type II:

The mean bad debt ratio is ≤ 3.5% when it is not.

The test statistics can be calculated by using the formula:

t = \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt{n}}}

where;

sample size n = 7

mean = 6+8+5+9+7+5+8 = 48

sample mean \overline x =\dfrac{48}{7}

\overline x = 6.86

sample standard deviation is :

s = \sqrt{\dfrac{\sum( x -\overline x)^2}{n-1}}

s = \sqrt{\dfrac{( 6 -6.86)^2+( 8-6.86)^2+  ( 5 -6.86)^2 + ...+( 7 -6.86)^2+ ( 5 -6.86)^2+( 8 -6.86)^2 }{7-1}}

s = 1.573

population  mean \mu = 3.5

Therefore, the test statistics is :

t = \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt{n}}}

t = \dfrac{6.86- 3.5}{\dfrac{1.573}{\sqrt{7}}}

t = \dfrac{3.36}{\dfrac{1.573}{2.65}}

t = \dfrac{3.36\times {2.65}}{{1.573}}

t = 5.660

At significance level of 0.01

t_{0.01} = 3.707  

P - value = P(T > 5.66)

P - value = 1 - (T < 5.66)

P - value = 1 - 0.9993

P-value = 0.0007

Therefore, since t_{0.01} < t , we reject the null hypothesis and conclude that the claim that the mean bad debt ratio for Ohio banks is higher than the mean for all financial institutions is true.

4 0
4 years ago
What is 1.04 to the 1/12 power
LiRa [457]
1.04 ^ 1/12 = 0.086666666
or
1.04 ^ 1/12 = 13/150
8 0
3 years ago
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