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hoa [83]
3 years ago
6

(7x10^-6) (8x 10^-5)

Mathematics
1 answer:
DENIUS [597]3 years ago
8 0

Answer:

56x^2 + 10^-11

Step-by-step explanation:

multiply the 7x and 8x and you get 56x^2

multiply the 10^-6 and 10^5-5 and you get 10^-11

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Look at the factors of 50 and 75.
Trava [24]

Answer:

The GCF of 50 and 75 is 25

Step-by-step explanation:

Factors of 50: 1, 2, 5, 10, 25, 50

Factors of 75: 1, 3, 5, 15, 25, 75

Therefore, the GCF of 50 and 75 is the greatest common factor that divides both 50 and 75

and from the factors of 50 and factors of 75, we will see that

25 divides 50 and also

25 divides 75

Hence, The GCF of 50 and 75 is 25

5 0
4 years ago
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Is w = 8 a solution to the equation 5 + w = 58? Explain
sp2606 [1]

No.

Since w = 8, you must replace the variable with the number associated to it.

So, it would be 5 + 8 = 58

5 + 8 is not equal to 58, it is equal to 13.

If you wanted to find out what w was, simply subtract 5 on both sides.

w = 58 - 5

8 0
3 years ago
What is the equation of a line, in general form, with a slope of -2 and a y-intercept of 8?
bearhunter [10]
The first equation, 2x+y-8=0 :)
4 0
3 years ago
I just wanted to say That I love everyone! And have a Wonderful and a bless day at school!!!! TRUMP 2020
Westkost [7]

Answer: Thank you, have a blessed day also

Step-by-step explanation:

5 0
3 years ago
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Probabilities. Please help
Anon25 [30]

In throwing a dice, there are 6 possible outcomes, namely 1, 2, 3, 4, 5 and 6.

P=(no. of favourable outcomes)/(no. of possible outcomes)

When we multiply the probability of an event with no. of trials, the we get the expected frequency of that event.

1) P(getting 1)=1/6

expected frequency of getting 1

=P(getting)1)×no. of trials

=1/6×600=100

But it is given that one is scored 200 times, so it makes a large difference from expected frequency, which is 100.

Therefore, the dice is not fair.

2) P(getting a tail)=0.3

estimate for the number of times the coin will land on a tail

=expected frequency of getting a tail

=P(getting a tail)×no. of trials

=0.3×150=45

3)P(getting a six)=2/3

expected frequency of getting a six

=P(getting a six)×no. of trials

=2/3×300=200

4)P(getting a three)=0.5

expected frequency of getting a three

=P(getting a three)×350

=0.5×350=175

3 0
3 years ago
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