Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
Answer:
144 ft
Step-by-step explanation:
I took a math test and I got this question wrong I saw my results and the answer was 144 ft I swear this is the correct answer.
If its correct please mark me as brainliest
Answer:
z^2x+10zx+8z^2+73z+7z/(z+8)(z+8)
(IMAGE DOWN BELOW)
Step-by-step explanation: Simplify the expression.
Hope this helps you out! ☺
We can use the equation [ f(x) = 16*4^(x-1) ] where x equals the year of study.
f(7) = 16*4(7-1)
f(7) = 16*4^6
f(7) = 16*4096
f(7) = 65,536
There is no option that resembles the correct answer.
Best of Luck!