Answer:
The probability that the maximum speed is at most 49 km/h is 0.8340.
Step-by-step explanation:
Let the random variable<em> </em><em>X</em> be defined as the maximum speed of a moped.
The random variable <em>X</em> is Normally distributed with mean, <em>μ</em> = 46.8 km/h and standard deviation, <em>σ</em> = 1.75 km/h.
To compute the probability of a Normally distributed random variable we first need to convert the raw score of the random variable to a standardized or <em>z</em>-score.
The formula to convert <em>X</em> into <em>z</em>-score is:
Compute the probability that the maximum speed is at most 49 km/h as follows:
Apply continuity correction:
P (X ≤ 49) = P (X < 49 - 0.50)
= P (X < 48.50)
*Use a <em>z</em>-table for the probability.
Thus, the probability that the maximum speed is at most 49 km/h is 0.8340.
Carissa value after x months=current+amount deposited
louan value after x months=current-amount taken out
carissa depositied=amount per month times x months=80x
louan take out=amount per month tiems x months=60x
when wil amount be equal
se equal
cariss=lousa
250+80x=1230-60x
add 60x both sides
250+140x=1230
minus 250 both sides
140x=980
divide both sides by 140
x=7
find how much that is
250+80(7)=250+560=810
7 months both have $810
Given:
Number of trips = 7
Distance from the school to the museum = 36 miles.
To find:
Write and solve equations to find how many miles the bus driver drove for the 7 trips.
Solution:
Let x be the number of trips and y be the total number of miles the bus driver drove.
Distance from the school to the museum = 36 miles.
1 trip means from the school to the museum and then from the museum to the school.
Distance covered in 1 trip = 2×36 = 72 miles.
Distance covered in x trips = 72x miles.
Substitute x=7 in the above equation to find the total distance the bus driver drove for the 7 trips.
Therefore, the bus driver drove 504 miles for the 7 trips.
$54.91
6.5% of 58.73.
Then minus that amount from 58.73
Mark brainliest please
