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svet-max [94.6K]

3 years ago

6

What is the expanded form of this number? 204.017

1 answer:

Anna [14]3 years ago

5 0

Answer:

(2×100) + (4×1) + (1÷10) + (7÷100)

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carl has a soccer game every 4th day and matt had one every 5th day. when will they have a game on the same day?

Valentin [98]

Every 20th day they will play

3 0

3 years ago

What two fractions are being<br> multiplied?

tiny-mole [99]

I see 2/3 and 1/2 being multiplied

3 0

3 years ago

What is the slope of the line y = 5x? Just write the<br> number for your answer.

vitfil [10]

Answer:

5

General Formulas and Concepts:

<u>Algebra I</u>

Slope-Intercept Form: y = mx + b

m - slope
b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

y = 5x

<u>Step 2: Break Function</u>

<em>Identify Parts</em>

Slope <em>m</em> = 5

y-intercept <em>b</em> = 0

5 0

3 years ago

Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago

Find the area of object and what is method

Alborosie

It would be...

(18 +28) divided by two

then take that and multiply it by the height - 5

the 6 in this equation doesn't matter because it is not the height of the shape

8 0

4 years ago