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aleksklad [387]
2 years ago
5

Can someone Just Give me a better understanding on Uniform and UnUniform Propability I will report if u take points

Mathematics
1 answer:
Irina18 [472]2 years ago
3 0

Answer:

Uniform is when you dress properly and working atire non uniform is when you dress freely

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How would i do number 2?
vekshin1

Answer:

m=2

Step-by-step explanation:

When you put a number into the inverse of a function (f^-1) you get the original number back.

Ex: f^-1(11) = (11-3)/2 = 4

f(4) = 2×4+3 = 11

So, f(-5)=-2

So, when x is -5,

f(x) = -2

f(x)=m(-5)+8

-2=m(-5) + 8

m=2

3 0
3 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
Korolek [52]

Answer:

A sample of 499 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this question, we have that:

\pi = 0.21

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03

We need a sample of n, which is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.21*0.79}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.21*0.79}

\sqrt{n} = \frac{1.645\sqrt{0.21*0.79}}{0.03}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.21*0.79}}{0.03})^2

n = 498.81

Rounding up

A sample of 499 is needed.

8 0
2 years ago
The authors of a paper titled "Age and Violent Content Labels Make Video Games Forbidden Fruits for Youth" carried out an experi
o-na [289]

Answer:

T = 290

Step-by-step explanation:

We can find the sum of all observations multiplying sample size (n) by sample mean (x).

Sum of all observations in the data set is,

T=n_{1} x_{1}+n_{2}x_{2}+n_{3}x_{3}+n_{4}x_{4}\\T=10(5.3)+10(7)+10(8.5)+10(8.2)\\T=53+70+85+82\\T=290

Hope this helps!

7 0
3 years ago
The picture has the 2 questions
Rzqust [24]

Answer:

Step-by-step explanation: quit

7 0
3 years ago
12 (5x-1) = 7x (2x +2)
murzikaleks [220]
60x - 12 = 14x^2 + 14x

Subtract 60x & Combine

-12 = 14x^2+14x-60x
-12= 14x^2-46x
Add 12
0= 14x^2-46x-14
7 0
3 years ago
Read 2 more answers
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