The area of a regular hexagon is
... A = (3√3)/2×s² . . . . . where s is the side length
Of course, the 6-sided figure will have a side length that is 1/6 of the perimeter.
... s = (48 in)/6 = 8 in
... A = (3√3)/2×(8 in)² = 96√3 in² . . . area of your regular hexagon
Answer:
225
Step-by-step explanation:
60 x 3 = 180 ($60 for each charity and there's 3 charities)
180 / (4/5) = 225 (if $180 is four fifths of his total just divide 180 by 4/5 to get the answer)
Answer: y=−2x+1
Step-by-step explanation:
To do part B, use the equation that you wrote for part A. We need to figure out what month number March of 2020 will be; we started in January 2015 at month 1; month 2 was Feb. 2015; month 3 was Mar. 2015; etc. to month 12 at Dec. 2015. Then month 13 will be Jan. 2016; month 13+12=25 will be Jan. 2017; month 25+12=37 will be Jan. 2018; month 37+12=49 will be Jan. 2019; month 49+12=61 will be Jan. 2020; month 62 will be Feb. 2020; and month 63 will be March 2020.
63 is the number you will substitute for x in the equation you've already written for part A.
the perimeter of the field is 442
width=w
the length of the field is 9 yards less than quadruple W
L=4x - 9
the perimeter is P=2L+2W
you can plug in the values
P= 2(4w-9) + 2W
plug in 442 for P
442= 2(4w- 9) + 2W
442= 8w - 36 + 2W
478 =8w + 2W
478= 10W
47.8 is your answer!!!
