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2 years ago

Hi can someone answer this question please thank you

Mathematics

2 answers:

lianna [129]2 years ago

6 0

Given that,

→ 5 : 20 :: x : 100

Then we have to,

find the second number to 100.

→ 100/20

→ 5

Now multiply each term by 5 in 5:20,

→ 5 × 5 : 20 × 5

→ 25 : 100

→ x = 25

Now these ratio will be,

→ 5 : 20 :: 25 : 100

Hence, the value of x is 25.

Zielflug [23.3K]2 years ago

5 0

Answer:

Step-by-step explanation:

5:20

We want to get the second number to 100

100/20 = 5

Multiply each term by 5

5*5 : 20*5

25 : 100

x is 25

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Step 1: Write as algebraic equations.

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g = b - 4

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Step 3: Simplify.

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ANSWER

b = 0.5(r + g - 2)

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2 years ago

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3 years ago

Read 2 more answers

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Sloan [31]

Answer:

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3 years ago

A one-parameter family of solutions of the de p' = p(1 − p) is given below.

tensa zangetsu [6.8K]

Answer:

A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

There is not a solution curve passing through the point(0,1).

Step-by-step explanation:

We have the following solution:

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

Does any solution curve pass through the point (0, 4)?

We have to see if P = 4 when t = 0.

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$4 = \frac{c_{1}}{1 + c_{1}}$

$4 + 4c_{1} = c_{1}$

$c_{1} = -\frac{4}{3}$

A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

Through the point (0, 1)?

Same thing as above

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$1 = \frac{c_{1}}{1 + c_{1}}$

$1 + c_{1} = c_{1}$

$0c_{1} = 1$

No solution.

So there is not a solution curve passing through the point(0,1).

3 0

3 years ago