If you're talking about the books in between, it will/be 20 books
Y-INTERCEPT

The y-intercept is where the equation/curve/parabola cosses the y-axis.
The y-axis is where x = 0. (The x-axis is where y = 0)
To find the y-intercept:

The y-intercept must be at (0, 10)
X-INTERCEPT (ROOTS/SOLUTIONS)

We need to use the quadratic formula
The quadratic formula helps us find what values of
make the equation = 0
Quadratic formula: 

The x-intercepts are at:

72.5+32.7= 105.2
Triangle angles have to equal 180
180-105.2= 74.8
Third angle= 74.8 degrees
The value of x in the triangle is 61.9°.