2 sides of a triangle are congruent to 2 sides on another triangle, and 1 angle on a triangle is congruent to another angle on another triangle
Answer:
-5/2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-29-(-9))/(15-7)
m=(-29+9)/8
m=-20/8
simplify
m=-5/2
Answer:
Minimum
Step-by-step explanation:
The zeros of a quadratic equation are the points at which the parabola intersects the x-axis.
(for some constant a)
The optimal value is the <u>y-coordinate of the vertex</u>.
The x-coordinate of the vertex is the midpoint of the zeros:
Therefore, the vertex will be in Quadrant IV and so the parabola opens <em>upwards </em>into Quadrant I.
So the optimal value is a MINIMUM since the vertex is the minimum point of the curve.
<u>Additional Information to create the equation of the quadratic</u>
Vertex form of quadratic equation:
where (h, k) is the vertex
To find the value of a, compare the constants of both equations:
So the final equation is:
Answer:
Step-by-step explanation:
Given
#We can evaluate by removing brackets and grouping the like terms:
Hence, the given problem can be solved to it's simplest form as