So anytime we have a slope and want to find the slope of a perpendicular line, we just have to remember a perpendicular line's slope is the negative reciprocal (reciprocal means flip the fraction). So if we had a slope of 3/4, the slope perpendicular to it would be - 4/3.
First we need to find our slope, to do this we take the change in y over the change in x like so:
(15-12)/(4-7) = - 3/4
The slope perpendicular to this is 4/3.
Please, see the offered decision:
1) common equation for lines is y=kx+b. If k₁=k₂ (for line 1 and line 2) ⇒ 'line 1' || 'line 2'.
2) for line 3x+5y=6 k= -3/5. It means (according to item 1) for unknown line k is the same (-3/5).
3) using points (0;3) it is easy to find parameter b (x=0, y=3) via y=kx+b:
3=0*(-3/5)+b ⇔ b=3.
4) finaly (k=-3/5; b=3):
Answer:
Step-by-step explanation:
for y intercept
we calculate f(0) and the value is y intercept
for the slope we have 2 points (x1,y1) and (x2,y2)
the slope is (y2-y1)/(x2-x1)
Answer:
$160
Step-by-step explanation:
Part A-
Step 1: 6(2k+5) - 20
Step 2: 6(2k) + 6(5) - 20
Step 3: 12k + 30 - 20
<h2><u>
12k + 10</u></h2><h2><u>
</u></h2><h3>Part B-</h3><h3>12(12.50) + 10</h3><h3>150 + 10</h3><h2><u>$160</u></h2>
X is equal 25 degrees. Line ac goes though the parallel lines. So bcd is x. Cdb is 180-50 equals 130. All angles add to 180. 180-130 equals 2X. So x equals 25.