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nikklg [1K]
2 years ago
15

Determine if the expression – 2 is a

Mathematics
1 answer:
Karo-lina-s [1.5K]2 years ago
5 0

Answer:

strictly speaking ... poly means MANY

3x+ 4 is a binomial (bi = 2 parts)

with only one part it can not be described as a "POLY-nomial"

Step-by-step explanation:

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Solve the equation: <br> 8y - 3 = бу + 17
balandron [24]

Hey!

------------------------------------------------

Steps To Solve:

8y - 3 = бу + 17

~Subtract 8y to both sides

8y - 3 - 8y = бу + 17 - 8y

~Simplify

-3 = -2y + 17

~Subtract 17 to both sides

-3 - 17 = -2y + 17 - 17

~Simplify

-20 = -2y

~Divide -2 to both sides

-20/-2 = -2y/-2

~Simplify

10 = y

------------------------------------------------

Hence, the answer is \Large\boxed{\mathsf{y~=~10}}

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Hope This Helped! Good Luck!

3 0
3 years ago
Read 2 more answers
Tell whether the angles are vertical or adjacent and solve for x. Solve 11 and 12 for 20 points and brainest.
stiv31 [10]

Answer:

11) x = 45

12) x = 30

Step-by-step explanation:

11)

3x + x = 180

4x = 180

x = 45

12)

4x = 5x - 30

4x - 5x = -30

-x = -30

x = 30

5 0
3 years ago
A line passes through the point (–2, 7) and has a slope of –5. A coordinate plane. What is the value of a if the point (a, 2) is
Nana76 [90]

Y = mx + c

7= (-5)(-2)+ c

7= 10 +c

7-10=c

-3=c

Equation of the line: y = -5x-3

Sub in (a, 2)

2= - 5(a)-3

2+3= -5a

5= - 5a

1= - a

A = -1

8 0
3 years ago
Read 2 more answers
A steel rod weighing 25 lb 11 oz is cut into three equal pieces. Find the weight of each piece of steel rod. Final answer must b
aleksandrvk [35]

Answer:

200 AND 50

Step-by-step explanation:

7 0
3 years ago
A bicycle lock has a four-digit code. The possible digits, 0 through 9, cannot be repeated. What is the probability that the loc
kozerog [31]
First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities
the second digit is any of the remaining 9, after having picked one. 
and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

so 

P(first digit is five)=\frac{n(first -digit- is- 5)}{n(all-codes)}= \frac{1*9*8*7 }{10*9*8*7 }= \frac{1}{10}=0.1

b. <span>What is the probability that the lock code will not contain the number 0? 

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6</span>
4 0
3 years ago
Read 2 more answers
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